xpath-2.0

相关标签：javascript jquery android 多少钱 iPhone

XSL: Recursion vs. Iteration

I\'m trying to understand XSL\'s handling of for-each. Initially I wrote a recursive choose-values function (filters out all strings that do not match a regexp pattern) as follows:[详细]

2023-04-13 03:29 分类：问答
How do I find the number of elements in a <xs:list> using XSLT?

I have an XML schema that contains the following type : <xs:simpleType name=\"valuelist\"> <xs:list itemType=\"xs:double\"/>[详细]

2023-04-12 09:51 分类：问答
Get tag attribute values, based on value of one attribute in xml

I 开发者_高级运维am making an application for android and am pulling and parsing the value of tag attributes from a xml file that is online.Say the xml file looks like this.[详细]

2023-04-06 03:50 分类：问答
XPATH matches function problem-- works but doesn't work

I\'m using Eclipse to run an XSL 2.0 (XPATH 2.0), and I have the following source: <testTop> <Level1 id=\"abc\" Text=\"from 1-2\"/>[详细]

2023-03-22 11:32 分类：问答
Does libxml2 support XPath 2.0 or not?

I\'ve tr开发者_运维百科ied to use the XPath 2.0 exp //span/string(.) in libxml2, but it doesn\'t work.[详细]

2023-03-18 17:31 分类：问答
Select elements with unique values

I\'m trying to parse an OpenOffice spreadsheet to obtain rows with unique values in the first column.[详细]

2023-03-16 22:02 分类：问答
Facing Problem with Xpath if then else concept

XML: <additionalFields> <field name=\"dataKey\">3868</field> <field name=\"distribution\">140</field>[详细]

2023-03-15 21:22 分类：问答
Creating a sequence of elements using Xpath 2.0 (as opposed to using XSLT)

I\'d like to create a sequence of elements in xpath 2.0 You can do something like: (\'a\',\'b\',\'c\')[详细]

2023-03-13 11:34 分类：问答
Xpath 'Like' operator to find value in html

I have an 开发者_JS百科html page which I would like to run a xPath query against to find any elements which have the id, name etc containing or like a value e.g name = \'tv_11223344\' or name = \'tv_1[详细]

2023-03-07 10:01 分类：问答
does JDK 6 support all features of XPath 2.0?

like for, sum, if, intersect...and if not, or not entirely, where can I find the details? And if it does, where can I f开发者_JS百科ind an official confirmation?According to the javadoc, Java 6 suppor[详细]

2023-03-01 04:26 分类：问答