lalr

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Learning bison: What are context-free grammars and LALR(1)?

I am reading this bison introduction. I have two questions and it will be great if someone can help me understand:[详细]

2023-03-30 17:24 分类：问答
Ambiguous grammar (using Bison)

I\'ve got a problem with an ambiguous grammar. I\'ve got this: %token identifier %token lolcakes %start program[详细]

2023-03-27 02:08 分类：问答
Simple Grammar for Lemon LALR Parser

I\'ve been stuck with this since a while now. I want to parse something as simple as: LIKES: word1 word2 .. wordN开发者_如何学C HATES: word1 word2 .. wordN[详细]

2023-03-22 06:01 分类：问答
Examples of LL(1), LR(1), LR(0), LALR(1) grammars?

Is there a good resource online with a collection of grammars for some of the major parsin开发者_开发技巧g algorithms (LL(1), LR(1), LR(0), LALR(1))?I\'ve found many individual grammars that fall into[详细]

2023-03-15 21:57 分类：问答
GPPG (bison) - How to implement an "expression expression" concept

We\'re using GPPG (essentially bison for C#) to generate a parser for a programming language. Everything is going great except for one really nasty bit. The language we are parsing has a sort of \"imp[详细]

2023-03-09 21:18 分类：问答
bison/yacc grammar disambiguation

I have following bison grammar (as part of more complex grammar): expression: IDENTIFIER CONST LAMBDA match_block[详细]

2023-03-08 14:43 分类：问答
Irony: How to give KeyTerm precedence over variable?

Relevant chunk of Irony grammar: var VARIABLE = new RegexBasedTerminal("variable", @"(?-i)\\$?\\w+");[详细]

2023-02-23 05:11 分类：问答
How to understand LALR Shift/Reduce Algorithm

I\'m trying to read Compiler Construction by Niklaus Wirth.On page 23 he starts to describe how LALR would parse the expression x*(y+z) given the following grammar:[详细]

2023-02-20 05:17 分类：问答
How to write LALR parser for some grammar in Java?

I want to write Java code to build a LALR parser f开发者_如何学Goor my grammar. Can someone please suggest some books or some links where I can learn how to write Java code for a LALR parser?Writing a[详细]

2023-02-18 09:05 分类：问答
Convert LALR to LL

I have this (working) LALR grammar for SABLECC: Package org.univpm.grail.sable; Helpers digit = [ \'0\' .. \'9\' ];[详细]

2023-02-10 04:46 分类：问答