fopen
PHP: failed to open stream: File exists
From a similar question I used this code to debug the failure of opening a file echo\'<pre>\'; error_reporting(E_ALL);[详细]
2023-02-18 08:29 分类:问答PHP: fopen to create folders
I need to know if there is any way to create new folder if the path doesn\'t exist. When I try to fopen() a path, it says NO such File or Directory exists I tried to open the 开发者_开发百科file using[详细]
2023-02-17 04:44 分类:问答problem writing in file
FILE *ExcelFile = fopen(\"testdata.csv\",\"w\"); if (ExcelFile == NULL) return -1; fprintf(ExcelFile,\"1 2 3\");[详细]
2023-02-14 16:41 分类:问答Is it a secure SSL data transmission? Or not?
I want to get an information from one website into a php script on another website via https. I read at www.php.net on the page of the fopen开发者_如何学C() function that this function supports HTTPS[详细]
2023-02-12 23:19 分类:问答Open a file, and print out a line with a particular number in C?
I know it is a very basic thing, but I\'m not very good at file handling in C. I\'m writing a custom error handler for something, and it needs to open a file, find a line by i开发者_StackOverflowts n[详细]
2023-02-12 00:47 分类:问答fopen is not opening a file stream... how do I resolve this?
I am trying to write a file and append data to it. Here is a snippet of my code.thresh is an unsigned short.[详细]
2023-02-11 17:39 分类:问答Force opening and reading zip files from php
This may be a simple question or a pretty complex one, ill let you be the deciders. Using PHP To open a zip file, extract the files to a directory and close the zip file is not a complicated class to[详细]
2023-02-11 09:50 分类:问答SImple C Program opening a file
I\'m trying to make a program to open a file, called \"write.txt\". #include <stdio.h> main() { FILE *fp;[详细]
2023-02-10 13:54 分类:问答Is prepending "http://" to a filename for PHP's fopen() safe enough to prevent reading local files?
I have a PHP script that accepts a file URL by GET and opens it with fopen. Is this solution safe enough or is it a security breach?[详细]
2023-02-09 23:44 分类:问答Dynamic fopen filepath in C
char filePath[200]; printf(\"Enter filepath: \\n\"); fgets(filePath, 200, stdin); f = fopen(filePath, \"r\");[详细]
2023-02-09 06:46 分类:问答