This

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Scala's "This" and MapLike

Say I wanted to extend Scala\'s MapLike trait with a concrete implementation, IntIntM开发者_StackOverflow社区ap. In order to do so, I need to implement the following methods,[详细]

2023-03-26 06:09 分类：问答
need to call a function which uses 'this' outside of the main activity in Android

This is the error I get when I try this call from an outside class. Thanks in Advance. Function Call GuessingLettersActivity.userGuess();[详细]

2023-03-25 22:47 分类：问答
How to define generic methods in node.js?

In node.js I struggle with classes/objects and the \'this\' keyword.E.g: function Set(arr,leq) { this.leq = leq ? leq : function(x,y) {return x<=y;};[详细]

2023-03-25 13:14 分类：问答
Problem with alert in smsRecevicer class

I am new here. I are making a app, where it must show a alert on sms message. I don\'t think I understand how i ex. can call a function from another class, when the function have a \"this\"-attribute.[详细]

2023-03-25 10:24 分类：问答
jQuery: Select a <p> tag within a <li>

I\'m trying to use jquery to fade out a <p> tag within a <li> when a delete button is selected.[详细]

2023-03-25 06:01 分类：问答
C++ this in constructor? [duplicate]

This question already has answers here: 开发者_运维问答 Closed 11 years ago. Possible Duplicate: c++ call constructor from constructor[详细]

2023-03-25 00:18 分类：问答
confusion over `this` keyword

I\'m reading crockford\'s Javascript: The Good Parts and am messing around with this piece of code from the lesson invocation patterns:[详细]

2023-03-24 21:37 分类：问答
C++ equivalent to Java this

In Java you can refer to the current object by doing: this.x = x. How do you do this in C++? Assume that each of these code examples are part of a class called Shape.[详细]

2023-03-24 17:24 分类：问答
return "this" in C++?

In Java开发者_JAVA百科 you can simply return this to get the current object. How do you do this in C++?[详细]

2023-03-24 13:56 分类：问答
in javascript, "this" seems to get lost when function in within an object's object

the object F has a function stored as this.fn and this.state.fn.can be called successfully as f.fn() but not as f.state.fn()[详细]

2023-03-24 09:58 分类：问答