memory-segmentation

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Why does the 8086 use an extra register to address 1MB of memory?

I heard that the 8086 has 16-bit registers which allow it to only address 64K of memory. Yet it is still able to address 1MB of memory which would require 20-bit registers. It does this by using anoth[详细]

2023-03-31 18:59 分类：问答
CONCEPT OF MOV AX,CS and MOV DS,AX

Can someone please explain the functions of these three instructions? ORG 1000H MOV AX,CS MOV DS,AX I know what the code, data, and extra segments are in theory, but:[详细]

2023-02-18 23:03 分类：问答
8086 segment selector

There\'s some \"supervisor\" bit to not let the \"user space\" do something li开发者_Python百科ke:[详细]

2023-01-30 20:23 分类：问答
Assembly Segmented Model 32bit Memory Limit

If a 32bit Operating System operated with a segmented memory model would their still be a 4GB limit? I was reading the Intel Pentium Processor Family Developer\'s Manual and it states that with a Seg[详细]

2023-01-22 21:41 分类：问答
What does "DS:[40207A]" mean in assembly?

0040103ACAL开发者_StackOverflow社区L DWORD PTR DS:[40207A]USER32.MessageBoxA What does DS: mean?The instruction is loading a new EIP value from memory at ds:[40207A]. i.e. there\'s a function pointe[详细]

2023-01-17 20:48 分类：问答
How can I prepend a `SS:` or `ES:` using AT&T Assembly Syntax

How c开发者_Python百科an I prepend a SS: or ES: using AT&T Assembly Syntax without adding in a .byte 0x36 or .byte 0x26?[详细]

2023-01-10 21:25 分类：问答
Assembler: How are segments used in 32bit systems?

From what I know, back in the days of 16bit PC\'s we had the Segment registers contain the address of each type of segment and you could access an offset with somethinglike this SS:[EDI], this would t[详细]

2023-01-09 11:42 分类：问答
physical address formula in 16 bit real mode: why multiply segment by 16?

physical address=16*selector+offset but i don\'t know why multiplying 16开发者_Python百科 by selector?In order to be \"programmer-compatible\" with the Z80, yet still be able to use more than 64 kiB o[详细]

2023-01-04 08:05 分类：问答
Ext js licensing [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.[详细]

2022-12-19 15:06 分类：问答