capturing-group

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Extract URL parameters with regex - repeating a capture group

I\'m attempting to extract the URL parameters via regex and am sooo close to getting it to work.I even know what the problem is: my regex is stumbling on repeated capture groups.But I simply cannot fi[详细]

2023-04-13 02:32 分类：问答
Regex Capturing Groups in Vala

Is there such a thing? I\'ve been looking around the Vala API and the 开发者_运维技巧Regex object seems to have no support for capturing groups so that I can reference them later. Is there currently a[详细]

2023-03-22 02:06 分类：问答
replace all captured groups

I need to transform something like: \"foo_bar_baz_2\" to \"fooBarBaz2\" I\'m trying to use this Pattern:[详细]

2023-03-21 11:17 分类：问答
Regex .NET attached named group

I want to get attached named group. Source text: 1/2/3/4/5|id1:value1|id2:value2|id3:value3|1/4/2/7/7|id11:value11|id12:value12|[详细]

2023-03-03 09:44 分类：问答
sed - Get only the replaced string from a multiline input & omit unmatched lines!

I want sed to omit all non-matching lines, and only output the replaced string (of the single/multiple intended line/s).[详细]

2023-02-21 20:19 分类：问答
Regular Expression capturing group with optional delimiter

Seemed like a simple problem, I need to extract a capturing group and optionally limit the group with a delimiting string.[详细]

2023-02-20 17:56 分类：问答
Regex enclosed with () Issue

I\'m having a regular expression (\\\\w+[ ]*|-\\\\w+[ ]*)(!=|<=|>=|=|<|>| not in | in | not like | lik开发者_如何学JAVAe )(.*)[详细]

2023-02-03 23:28 分类：问答
Iterative regex capturing in C#

I have to read in a file that contains a number of coordinates. The file is structured in the following way:开发者_运维百科[详细]

2023-01-20 01:34 分类：问答
How do I use regular expression capturing groups with JFlex?

Although this question is about JFlex, it probably applies to other scanner generators such as lex, flex as well.[详细]

2023-01-19 22:23 分类：问答
Regex - Saving Repeating Captured Group

This is what I\'m doing 开发者_开发问答a = \"%span.rockets#diamonds.ribbons.forever\" a = a.match(/(^\\%\\w+)([\\.|\\#]\\w+)+/)[详细]

2023-01-15 03:00 分类：问答