目录
- 一、wapper介绍
- 二、AbstractWrapper
一、wapper介绍
二、AbstractWrapper
注意:以下条件构造器的方法入参中的 column 均表示数据库字段
1.ge、gt、le、lt、isNull、isNotNull
@Test public void testSelect() { QueryWrapper<User> queryWrapper = new QueryWrapper<>(); queryWrapper.ge("age", 28); List<User> users = userMapper.se编程lectList(queryWrapper); System.out.println(users); }
2.eq、ne
注意:seletOne返回的是一条实体记录,当出现多条时会报错
@Test public void testSelectOne() { QueryWrapper<User> queryWrapper = new QueryWrapper<>(); queryWrapper.eq("name", "Tom"); User user = userMapper.selectOne(queryWrapper); System.out.println(user); }
SELECT id,name,age,email,create_time,update_time,deleted,version FROM user WHERE deleted=0 AND name = ?
3.between、notBetween
包含大小边界
@Test public void testSelectCount() { QueryWrapper<User> queryWrapper = new QueryWrapper<>(); queryWrapper.between("age", 20, 30); Integer count = userMapper.selectCount(queryWrapper); System.out.println(count); }
SELECT COUNT(1) FROM user WHERE deleted=0 AND age BETWEEN ? AND ?
4.allEq
@Thttp://www.devze.comest public void testSelectList() { QueryWrapper<User> queryWrapper = new QueryWrapper<>编程客栈(); Map<String, Object> map = new HashMap<>(); map.put("id", 2); map.put("name", "Jack"); map.put("age", 20); queryWrapper.allEq(map); List<User> users = userMapper.selectList(queryWrapper); users.forEach(System.out::println); }
SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 AND name = ? AND id = ? AND age = ?
5.like、notLike、likeLeft、likeRight
selectMaps返回Map集合列表
@Test public void testSelectMaps() { QueryWrappphper<User> queryWrapper = new QueryWrapper<>(); queryWrapper .notLike("name", "e") .likeRight("email", "t"); List<Map<String, 编程Object>> maps = userMapper.selectMaps(queryWrapper);//返回值是Map列表 maps.forEach(System.out::println); }
SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 AND name NOT LIKE ? AND email LIKE ?
6.in、notIn、inSql、notinSql、exists、notExists
in、notIn:
- notIn(“age”,{1,2,3})—>age not in (1,2,3)
- notIn(“age”, 1, 2, 3)—&开发者_JS培训gt;age not in (1,2,3)
inSql、notinSql:可以实现子查询
- 例: inSql(“age”, “1,2,3,4,5,6”)—>age in (1,2,3,4,5,6)
- 例: inSql(“id”, “select id from table where id < 3”)—>id in (select id from table where id < 3)
@Test public void testSelectObjs() { QueryWrapper<User> queryWrapper = new QueryWrapper<>(); //queryWrapper.in("id", 1, 2, 3); queryWrapper.inSql("id", "select id from user where id < 3"); List<Object> objects = userMapper.selectObjs(queryWrapper);//返回值是Object列表 objects.forEach(System.out::println); }
SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 AND id IN (select id from user where id < 3)
7.or、and
注意:这里使用的是 UpdateWrapper
不调用or则默认为使用 and 连
@Test public void testUpdate1() { //修改值 User user = new User(); user.setAge(99); user.setName("Andy"); //修改条件 UpdateWrapper<User> userUpdateWrapper = new UpdateWrapper<>(); userUpdateWrapper .like("name", "h") .or() .between("age", 20, 30); int result = userMapper.update(user, userUpdateWrapper); System.out.println(result); }
UPDATE user SET name=?, age=?, update_time=? WHERE deleted=0 AND name LIKE ? OR age BETWEEN ? AND ?
8.嵌套or、嵌套and
这里使用了lambda表达式,or中的表达式最后翻译成sql时会被加上圆括号
@Test public void testUpdate2() { //修改值 User user = new User(); user.setAge(99); user.setName("Andy"); //修改条件 UpdateWrapper<User> userUpdateWrapper = new UpdateWrapper<>(); userUpdateWrapper .like("name", "h") .or(i -> i.eq("name", "李白").ne("age", 20)); int result = userMapper.update(user, userUpdateWrapper); System.out.println(result); }
UPDATE user SET name=?, age=?, update_time=?
WHERE deleted=0 AND name LIKE ?
OR ( name = ? AND age <> ? )
9.orderBy、orderByDesc、orderByAsc
@Test public void testSelectListOrderBy() { QueryWrapper<User> queryWrapper = new QueryWrapper<>(); queryWrapper.orderByDesc("id"); List<User> users = userMapper.selectList(queryWrapper); users.forEach(System.out::println); }
SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 ORDER BY id DESC
10.last
直接拼接到 sql 的最后
注意:只能调用一次,多次调用以最后一次为准 有sql注入的风险,请谨慎使用
@Test public void testSelectListLast() { QueryWrapper<User> queryWrapper = new QueryWrapper<>(); queryWrapper.last("limit 1"); List<User> users = userMapper.selectList(queryWrapper); users.forEach(System.out::println); }
SELECT id,name,age,email,create_time,update_time,deleted,version
FROM user WHERE deleted=0 limit 1
11.指定要查询的列
@Test public void testSelectListColumn() { QueryWrapper<User> queryWrapper = new QueryWrapper<>(); queryWrapper.select("id", "name", "age"); List<User> users = userMapper.selectList(queryWrapper); users.forEach(System.out::println); }
SELECT id,name,age FROM user WHERE deleted=0
12.set、setSql
最终的sql会合并 user.setAge(),以及 userUpdateWrapper.set() 和 setSql() 中 的字段
@Test public void testUpdateSet() { //修改值 User user = new User(); user.setAge(99); //修改条件 UpdateWrapper<User> userUpdateWrapper = new UpdateWrapper<>(); userUpdateWrapper .like("name", "h") .set("name", "老李头")//除了可以查询还可以使用set设置修改的字段 .setSql(" email = '123@qq.com'");//可以有子查询 int result = userMapper.update(user, userUpdateWrapper); }
UPDATE user SET age=?, update_time=?, name=?, email = ‘123@qq.com’ WHERE deleted=0 AND name LIKE ?
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