python实现自动售货机_开发_开发者_运维开发者技术经验分享

本文实例为大家分享了python实现自动售货机的具体代码，供大家参考，具体内容如下

自动售货机代码

while True:
n=input('请选择操作:')
if n=='r':
 l=input('请输入货物数量:')
 v=l.split('-')
 numA1=int(v[0])
 numA2=int(v[1])
 numA3=int(v[2])
 numA4=int(v[3])
 numA5=int(v[4])
 numA6=int(v[5])
 t=input('请输入硬币数量:')
 u=t.split('-')
 yiyuan=int(u[0])
 liangyuan=int(u[1])
 wuyuan=int(u[2])
 shiyuan=int(u[3])
 print('S001:Initialization is successful')
elif n=='q':
  print('会员管理'.center(50,'*'))

  print("""
       操作目录
       0-货物剩余量
       1-钱盒""")
  while True:
   c=input()
   if c=='0':

    print('A1 %d A2 %d A3 %d A4%d A5 %d A6 %d' %(numA1,numA2,numA3,numA4,numA5,numA6))
   elif c=='1':
    print('1yuan coin number=%d 2yuan coin number=%d 5yuan coin number=%d 10 yuan coin number=%d' %(yiyuan,liangyuan,wuyuan,shiyuan))
elif n=='p':
 counname=input('请选择商品:')
 if counname=='1':
  if numA1<=0:
      print('E007:The goods sold out')
  else:
    m=input('请输入现金:')
    if m=='1':
      print('S003:Buy success,balance=1')
      print('E009:Work failure')
      numA1-=1
      yiyuan+=1
    elif m=='2':
      print('S003:Buy success,balance=1')
      numA1-=1
      liangyuan+=1
      yiyuan-=1
      print('找您一元')
    elif m=='5':
      if yiyuan*1+liangyuan*2<5:
        print('E003:Change is not enough,pay fail')
      else:
        print('S002:Pay success,balance=1')
        print('S003:Buy success,balance=1')
        numA1-=1
        wuyuan+=1
        liangyuan-=2
        print('找您4元')
    elif m=='10':
      if yiyuan*1+liangyuan*2<10:
        print('E003:Change is not enough,pay fail')
      else:
        print('S002:Pay success,balance=1')
        print('S003:Buy success,balance=1')
        shiyuan+=1
        wuyuan-=1
        liangyuan-=2
        print('找您9元')
    else:
      print('E002:Denomination error')

 elif counname == '2':
  if numA2 <= 0:
    print('E007:The goods sold out')
  else:
    m=input('请输入现金:')
    if m == '1':
      print('E008:Lack of balance')
    elif m == '2':
      print('S003:Buy success,balance=1')
      print('E009:Work failure')
      numA2 -= 1
      liangyuan += 1
    elif m == '5':
      if yiyuan * 1 + liangyuan * 2 < 5:
        print('E003:Change is not enough,pay fail')
      else:
        print('S002:Pay success,balance=2')
        print('S003:Buy success,balance=1')
        wuyuan+=1
        yiyuan-=1
        liangyuan-=1
        print('找您三元')
    elif m == '10':
      if yiyuan * 1 + liangyuan * 2 < 10:
        print('E003:Change is not enough,pay fail')
      else:
        print('S002:Pay success,balance=2')
        print('S003:Buy success,balance=1')
        numA2-=1
        shiyuan+=1
        wuyuan-=1
        yiyuan-=1
        lhttp://www.cppcns.comiangyuan-=2
        print('找您8元')
    else:
      print('E002:Denomination error')
 elif counname == '3':
  if numA3 <= 0:
    print('E007:The goods sold out')
  编程客栈else:
    m=input('请输入现金:')
    if m == '1':
      print('E008:Lack of balance')
    elif m == '2':
      print('E008:Lack of balance')
    elif m == '5':
      if yiyuan * 1 + liangyuan * 2 < 5:
        print('E003:Change is not enough,pay fail')
      else:
        print('S002:Pay success,balance=3')
        print('S003:Buy success,balance=1')
        numA3-=1
        wuyuan += 1
        liangyuan -= 1
        print('找您三元')
    elif m == '10':
      if yiyuan * 1 + liangyuan * 2 < 10:
        print('E003:Change is not enough,pay fail')
      else:
        print('S002:Pay success,balVcfEvance=3')
        print('S003:Buy success,balance=1')
        numA3 -= 1
        shiyuan += 1
        wuyuan -= 1
        liangyuan -= 1
        print('找您7元')
    else:
      print('E002:Denomination error')
 elif counname == '4':
  if numA4 <= 0:
    print('E007:The goods sold out')
  else:
    m=input('请输入现金:')
    if m == '1':
      print('E008:Lack of balance')
    elif m == '2':
      print('E008:Lack of balanceVcfEv')
    elif m == '5':
      if yiyuan * 1 + liangyuan * 2 < 5:
        print('E003:Change is not enough,pay fail')
      else:
        print('S002:Pay success,balance=4')
        print('S003:Buy success,balance=1')
        numA4 -= 1
        wuyuan += 1
        yiyuan -= 1
        print('找您1元')
    elif m == '10':
      if yiyuan * 1 + liangyuan * 2 < 10:
        print('E003:Change is not enough,pay fail')
      else:
        print('S002:Pay success,balance=4')
        print('S003:Buy success,balance=1')
        numA4 -= 1
        shiyuan += 1
        wuyuan -= 1
        yiyuan -= 1
        print('找您6元')
    else:
      print('E002:Denomination error')
 elif counname == '5':
  if numA5 <= 0:
    print('E007:The goods sold out')
  else:
    m=input('请输入现金:')
    if m == '1':
      print('E008:Lack of balance')
    elif m == '2':
      print('E008:Lack of balance')
    elif m == '5':
      print('E008:Lack of balance')
    elif m == '10':
      if yiyuan * 1 + liangyuan * 2 < 10:
        print('E003:Change is not enough,pay fail')
      else:
        print('S002:Pay success,balance=6')
        print('S003:Buy success,balance=1')
        numA5 -= 1
        shiyuan += 1
        liangyuan-=2
        print('找您4元')
    else:
      print('E002:Denomination error')
 elif counname == '6':
  if numA6 <= 0:
    print('E007:The goods sold out')
  else:
    m=input('请输入现金:')
    if m == '1':
      print('E008:Lack of balance')
    elif m == '2':
      print('E008:Lack of balance')
    elif m == '5':
        print('S003:Buy success,balance=1')
        print('E009:Work failure')
        numA6 -= 1
        wuyuan+=1
    elif m == '10':
      if yiyuan * 1 + liangyuan * 2 < 10:
        print('E003:Change is not enough,pay fail')
      else:
        print('S002:Pay success,balance=5')
        print('S003:Buy success,balance=1')
        numA6 -= 1
        shiyuan += 1
        wuyuan -= 1
        print('找您5元')
 else:
  print('E006:Goods does not exist')
else:
   print('操作无效')

解释说明：钱币盒内只有，一元，两元，五元，十元的硬币；顾客也只能投入这些，钱币盒内一元和两元的总面额必须大于顾客给的面额，顾客一次只能投一次钱并买一件商品，但可以多次投入多次购买。货物数量和钱币数量由管理员初始化设定，管理员也可以查看钱币及货物数量，但查看完毕必须退出。如果编程客栈投入钱币恰好等于商品价格，则购买成功并提示余额为0，工作失败，意味后续无法购买。

r——–初始化，必须初始化后才能执行程序

q——-管理员查看钱盒和货物信息

p——-顾客购买商品及付款及退钱

如图有：

python实现自动售货机