SpringSecurity报错authenticationManager must be spec的解决

目录

• 有两个地方要改下
• 然后在过滤器里面显示的设置一下
• 顺便贴一下两个类的完整代码
• 过滤器
• 配置文件

在重写类UsernamePasswordAut开发者_Python学习henticationFilter时抛出了这个异常，字面上理解是authenticationManager不明确，所以要显示的注入。

有两个地方要改下

首先要在配置文件重写authenticationManager

    @Bean
    @Override
    protected AuthenticationManager authenticationManager() throws Exception {
        return super.authenticationManager();
    }

然后在过滤器里面显示的设置一下

    @Autowired
    @Override
    public void setAuthenticationManager(AuthenticationManager authenticationManager) {
        super.setAuthenticationManager(authenticationManager);
    }

编程客栈

顺便贴一下两个类的完整代码

仅供参考：

过滤器

@Component
public class TokenLoginFilter extends UsernamePasswordAuthenticationFilter {
    @Autowired
    JwtTokenUtils jwtTokenUtils;
 
    public TokenLoginFilter() {
        this.setPostOnly(false);
        this.setRequiresAuthenticationRequestMatcher(new AntPathRequestMatcher("/login","POST"));
    }
 
    @Override
    public Authentication attemptAuthentication(HttpServletRequest request, HttpServletResponse response) throws AuthenticationException {
        //获取表单提交数据
        try {
            UserInfo user = new ObjectMapper().readValue(request.getInputStream(), UserInfo.class);
            return super.getAuthenticationManager().authenticate(new UsernamePasswordAuthenticationToken(user.getLoginName(),user.getPassword(),
                    new ArrayList<>()));
        } catch (IOException e) {
            e.printStackTrace();
            throw new RuntimeException();
        }
    }
 
    @Override
    protected void successfulAuthentication(HttpServletRequest request, HttpServletResponse response, FilterChain chain, Authentication authResult) throws IOException, ServletException {
        UserSecurity userSecurity = (UserSecurity) authResult.getPrincipal();
        String token = jwtTokenUtils.createToken(userSecurity.getUsername());
        ResponseUtils.out(response, R.ok(token));
    }
 
    @Override
    protected void unsuccessfulAuthentication(HttpServletRequest request, HttpServletResponse response, AuthenticationException failed) throws IOException, ServletException {
        ResponseUtils.out(response, R.fail(ServiceError.LOGIN_FAIL));
    }
 
    @Autowired
    @Override
    public void setAuthenticationManager(AuthenticationManager authenticationManager) {
        super.setAuthenticationManager(authenticationManager);
    }
}

配置文件

@Configuration
@EnablejavascriptWebSecurity
@EnableGlobalMethodSecurity(prePostEnabled = true)
public class SecurityConfig extends WebSecurityConfigurerAdapter {
 
    @Autowired
    UserInfoServiceImpl userInfoService;
 
    @Autowired
    JwtAuthorizationTokenFilter jwtAuthorizationTokenFilter;
 
    @Autowired
    TokenLoginFilter tokenLogjsinFilter;
 
    @Autowired
    JwtAuthenticationEntryPoint jwtAuthenticationEntryPoint;
 
    @Autowired
    public void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(userInfoService).passwordEncoder(ppythonasswordEncoderBean());
    }
 
    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.exceptionHandling()
                .authenticationEntryPoint(jwtAuthenticationEntryPoint)
                .and().csrf().disable()
                .authorizeRequests()
                .antMatchers("/login").permitAll()
                .antMatchers("/hello").permitAll()
                .antMatchers(HttpMethod.OPTIONS, "/**").anonymous()
                .anyRequest().authenticated()
                .and()
                .addFilterAt(tokenLoginFilter, UsernamePasswordhttp://www.devze.comAuthenticationFilter.class)
                .addFilterAfter(jwtAuthorizationTokenFilter, TokenLoginFilter.class).httpBasic();
 
    }
 
    @Bean
    public PasswordEncoder passwordEncoderBean() {
        return new BCryptPasswordEncoder();
    }
 
    @Bean
    @Override
    protected AuthenticationManager authenticationManager() throws Exception {
        return super.authenticationManager();
    }
}

以上为个人经验，希望能给大家一个参考，也希望大家多多支持我们。