目录
- 一、引用的python模块
- 二、实现过程
- 三、演示效果
一、引用的python模块
Crypto:
Python中一个强大的加密模块,提供了许多常见的加密算法和工具。它建立在pyc.ypodome或pyc.ypto等底层加密库之上,为Python程序员提供了简单易用的API,使其可以轻松地实现各种加密功能。
commands:
commands 模块是 Python 的内置模块,它主要有三个函数:
FUNCTIONS
getoutput(cmd)Return output (stdout or stderr) of executing cmd in a shell.getstatus(file)Return output of "ls -ld <file>" in a string.getstatusoutput(cmd)Return (status, 'output) of executing cmd in a shell.
SYS: 基础系统模块
sys模块是与python解释器交互的一个接口。sys 模块提供了许多函数和变量来处理 Python 运行时环境的不同部分。
二、实现过程
python脚本如下:
import crypt import commands import sys def testPass(user,cryptPass,ipaddr): android #dictfile=open('dictionary.txt','r') start_index=cryptPass.find("$") finish_index=cryptPass.rfind("$") salt=cryptPass[start_index:finish_index+1] dictfile=open('/root/dict.txt','r') pwd_suffix = ['','.','..','!','!@#','1','123','1234','12345','123456','888','666','999','2006','2007','2008','2009','2010','2011','2012','2013','2014','2015','2016','2017','2018','2019'] for sfx in pwd_suffix: #print user+sfx for separator in ['','@','#','&']: cryptWord=crypt.crypt('%s%s%s'%(user,separator,sfx),salt) if cryptWord==cryptPass: #print ipaddr + " [+] Found Password: " +user+'/'+user+sfx+ " \n" print '%s [+] Found Passwd: %s/%s%s%s \n'%(ipaddr,user,user,separator,sfx) break cryptWord=crypt.crypt('%s%s%s'%(user,sfx,separator),salt) if cryptWord==cryptPass: #print ipadphpdr + " [+] Found Password: " +user+'/'+user+sfx+ " \n" print '%s [+] Found Passwd: %s/编程客栈%s%s%s \n'%(ipaddr,user,user,sfx,separator) php break for word in dictfile.readlines(): #print word word=word.stripjavascript() cryptWord=crypt.crypt(word,salt) if cryptWord==cryptPass: print ipaddr + " [+] Found Password: " +user+'/'+word+ " \n" break print('[-] Password not found!') def main(): cmd = "ifconfig|grep \"inet addr\"|grep -v 127.0.0.1|awk '{print $2}'" ipaddr = commands.getoutput(cmd).replace('addr:','').replace('\n','|') shadowfile=open('/etc/shadow') for line in shadowfile.readlines(): user=line.split(':')[0] cryptPass=line.split(':')[1].strip('\n') if not (cryptPass.startswith('*') or cryptPass.startswith('!')): print "[*] Cracking Password For: " +user testPass(user,cryptPass,ipaddr) if __name__=='__main__': main()
注:破解密码有两种方式,一种是通过脚本pwd_suffix定义的后缀,另一种是调用密码字典库(/root/dict.txt)来破解。
三、演示效果
创建一个测试用户testuser,密码设置成123456,然后执行检测脚本。滴,弱密码已被发现!
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