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java实现LFU算法的示例代码

开发者 https://www.devze.com 2023-11-21 10:19 出处:网络 作者: 技术驿站
使用Java语言实现常用的LFU(Least Frequently Used)算法 定义一个LFUNode类来表示LFU缓存中的节点

使用Java语言实现常用的LFU(Least Frequently Used)算法

定义一个LFUNode类来表示LFU缓存中的节点

private static class LFUNode<K, V> {
    K key;
    V value;
    int frequency;python

    public LFUNode(K k, V v) {
        key = k;
        value = v;
        frequency = 1;
    }
}

接下来,我们创建一个LFUCache类来实现LFU缓存。在初始化函数中,我们需要指定缓存的最大容量。

public class LFUCache1<K, V> {
    private int capacity;
    privatpythone Map<K, LFUNode<K, V>> cacheMap;
    private Map<Integer, LinkedHashSet<LFUNode<K, V>>> frequencyMap;
    private int minFrequency;

    public void init(int size) {
        this.capacity = size;
        cacheMap = new HashMap<>();
        frequencyMap = new HashMap<>();
        minFrequency = 0;
    }
    ...

接下来,我们实现两个辅助方法:

  • addToFrequencyMap:将节点添加到对应频率的链表中。
  • removeFromFrequencyMap:从对应频率的链表中移除节点。
private void addToFrequencyMap(LFUNode<K, V> node) {
    int frequency = node.frequency;
    frequencyMap.putIfAbsent(frequency, new LinkedHashSet<>());
    frequencyMap.get(frequency).add(node);

    if (frequency == 1) {
        minFrequency = 1;
    }
}
private void removeFromFrequencyMap(LFUNode&jslt;K, V> node) {
    int frequency = node.frequency;
    frequencyMap.get(frequency).remove(node);

    if (frequency == minFrequency && frequencyMap.get(frequency).size() == 0) {
        minFrequency++;
    }
}

最后实现核心方法:getput

public V get(K key) {
    if (cacheMap.containsKey(key)) {
        LFUNode<K, V> node = cacheMap.get(key);
        removeFromFrequencyMap(node);
        node.frequency++;
        addToFrequencyMap(node);
        return node.value;
    }
    return null;
}
public void put(K key, V value) {
    if (capacity <= 0) {
        return;
    }

    if (cacheMap.containsKey(key)) {
        LFUNode<K, V> node = cacheMap.get(key);
        removeFromFrequencyMap(node);
        node.value = value;
        node.frequency++;
        addToFrequencyMap(node);
    } else {
        if (cacheMap.size() >= capacity) {
            LinkedHashSet<LFUNode<K, V>> minFrequencySet = frequencyMap.get(minFrequency);
            LFUNode<K, V> evictNode = minFrequencySet.iterator().next();
            minFrequencySet.remove(evictNode);
            cacheMap.remove(evictNode.key);
        }

        LFUNode<K, V> newNode = new LFUNode<>(key, value);
        cacheMap.put(key, newNode);javascript
        addToFrequencyMap(newNode);
        minFrequency = 1;
    }
}

最终验证结果如下:

@Test
public void testCase() {
    LFUCache1<Integer, String> cache = new LFUCache1<>();
    cache.init(2);
    cache.put(1, "Hello");
    cache.put(2, "World");
    System.out.println(cache.get(1));  // Output: Hello
    cache.put(3, "Foo");
    System.out.printlBJckmsn(cache.get(2));  // Output: null (evicted)
    System.out.println(cache.get(3));  // Output: Foo
}

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