C语言实现经典扫雷小游戏的示例代码

目录

• 一、游戏简介
• 二、游戏实现
• 1.初始化棋盘
• 2.打印棋盘
• 3.布置雷
• 4.排查雷
• 三、源文件
• 1.game.h
• 2.game.c
• 3.Test.c

开发者_C培训

一、游戏简介

游戏初始界面有两个选择，选项“1”为开始游戏，选项“0”为退出游戏；选择开始游戏之后将会打印出9*9的棋盘，此时系统已经为游戏设置了10个雷，输入坐标之后将会打印出此坐标周围八个位置有几个雷，如果踩到了雷，那么游戏结束，打印出所有雷的位置。

二、游戏实现

1.初始化棋盘

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
	int i = 0;
	intjs j = 0;
	for (i = 0; i < rows; i++)
	{
		for (j = 0; j < cols; j++)
		{
			board[i][j] = set;
		}
	}
}

2.打印棋盘

void DisplayBoard(char board[ROWS][COLS], int row, int col)
{
	int i = 0;
	int j = 0;
	for (i = 0; i <= col; i++)
	{
		printf("%d ", i);
	}
	printf("\n");
	for (i = 1; i <= row; i++)
	{
		printf("%d ", i);
		for (j = 1; j <= col; j++)
		{
			printf("%c ", board[i][j]);
		}
		printf("\n");
	}
}

3.布置雷

void SetMine(char mine[ROWS][COLS], int row, int col)
{
	int count = EASY_COUNT;
	while (count)
	{
		int x = rand() % row + 1;
		int y = rand() % col + 1;
		if (mine[x][y] == '0')
		{
			mine[x][y] = '1';
			count--;
		}
	}
}

4.排查雷

void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
	int x = 0;
	int y = 0;
	int win = 0;
	//9*9 - EASY_COUNT = 71

	while (win < row * col - EASY_COUNT)
	{
		printf("请输入排查的坐标:");
		scanf("%d%d", &x, &y);
		if (x >= 1 && x <= row && y >= 1 && y <= col)
		{
			if (mine[x][y] == 编程'1')
			{
				printf("很遗憾，你被炸死了\n");
				DisplayBoard(mine, row, col);
				break;
			}
			else
			{
				int count = GetMineCount(mine, x, y);
				show[x][yandroid] = count + '0';
				DisplayBoard(show, row, col);
				win++;
			}
		}
		else
		{
			printf("请注意，坐标有误，重新输入！\n");
		}
	}
	if (win == row * col - EASY_COUNT)
	{
		printf("恭喜你，排雷成功\n");
		DisplayBoard(mine, row, col);
	}
}

int GetMineCount(char mine[ROWS][COLS], int x, int y)
{
	return (mine[x - 1][y] +
		mine[x - 1][y - 1] +
		mine[x][y - 1] +
		mine[x + 1][y - 1] +
		mine[x + 1][y] +
		mine[x + 1][y + 1] +
		mine[x][y + 1] +
		mine[x - 1][y + 1] - 8 * '0');
}

GetMineCount（）函数为获取输入的坐标周围八个位置雷的数量

三、源文件

1.game.h

#define _CRT_SECURE_NO_WARNINGS
#define ROW 9
#define COL 9
#define ROW编程客栈S ROW+2
#define COLS COL+2
#define EASY_COUNT 10
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
void InitBoard(char board[ROWS][COLS], int rows, int cols,char set);
void DisplayBoard(char board[ROWS][COLS], int row, int col);
void SetMine(char board[ROWS][COLS], int row, int col);
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

2.game.c

#include"game.h"
void InitBoard(char board[ROWS][COwww.devze.comLS], int rows, int cols, char set)
{
	int i = 0;
	int j = 0;
	for (i = 0; i < rows; i++)
	{
		for (j = 0; j < cols; j++)
		{
			board[i][j] = set;
		}
	}
}
void DisplayBoard(char board[ROWS][COLS], int row, int col)
{
	int i = 0;
	int j = 0;
	for (i = 0; i <= col; i++)
	{
		printf("%d ", i);
	}
	printf("\n");
	for (i = 1; i <= row; i++)
	{
		printf("%d ", i);
		for (j = 1; j <= col; j++)
		{
			printf("%c ", board[i][j]);
		}
		printf("\n");
	}
}

void SetMine(char mine[ROWS][COLS], int row, int col)
{
	int count = EASY_COUNT;
	while (count)
	{
		int x = rand() % row + 1;
		int y = rand() % col + 1;
		if (mine[x][y] == '0')
		{
			mine[x][y] = '1';
			count--;
		}
	}
}
int GetMineCount(char mine[ROWS][COLS], int x, int y)
{
	return (mine[x - 1][y] +
		mine[x - 1][y - 1] +
		mine[x][y - 1] +
		mine[x + 1][y - 1] +
		mine[x + 1][y] +
		mine[x + 1][y + 1] +
		mine[x][y + 1] +
		mine[x - 1][y + 1] - 8 * '0');
}
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
	int x = 0;
	int y = 0;
	int win = 0;
	//9*9 - EASY_COUNT = 71

	while (win < row * col - EASY_COUNT)
	{
		printf("请输入排查的坐标:");
		scanf("%d%d", &x, &y);
		if (x >= 1 && x <= row && y >= 1 && y <= col)
		{
			if (mine[x][y] == '1')
			{
				printf("很遗憾，你被炸死了\n");
				DisplayBoard(mine, row, col);
				break;
			}
			else
			{
				int count = GetMineCount(mine, x, y);
				show[x][y] = count + '0';
				DisplayBoard(show, row, col);
				win++;
			}
		}
		else
		{
			printf("请注意，坐标有误，重新输入！\n");
		}
	}
	if (win == row * col - EASY_COUNT)
	{
		printf("恭喜你，排雷成功\n");
		DisplayBoard(mine, row, col);
	}
}

3.Test.c

#include"game.h"

void menu()
{
	printf("********************\n");
	printf("*欢迎来到扫雷小游戏*\n");
	printf("***** 1.play *******\n");
	printf("***** 0.exit *******\n");
	printf("********************\n");
}
void game()
{
	//存放布置好的雷的信息
	char mine[ROWS][COLS] = { 0 };//'0'-不是雷
	//存放排出的雷的信息
	char show[ROWS][COLS] = { 0 };//'*'-神秘-未排查
	//初始化
	InitBoard(mine, ROWS, COLS, '0');
	InitBoard(show, ROWS, COLS, '*');
	//打印棋盘
	//DisplayBoard(mine,ROW,COL);
	//DisplayBoard(show,ROW,COL);
	//布置雷
	SetMine(mine,ROW,COL);
	//DisplayBoard(mine, ROW, COL);
	DisplayBoard(show, ROW, COL);
	//排查雷
	FindMine(mine, show, ROW, COL);
}
void test()
{
	int input = 0;
	srand((unsigned int)time(NULL));
	do
	{
		menu();
		printf("请选择:");
		scanf("%d", &input);
		switch (input)
		{
		case 1:
			game();
			//printf("扫雷\n");
			break;
		case 0:
			printf("退出游戏\n");
			break;
		default:
			printf("选择错误\n");
			break;
		}
	} while(input);
}
int main()
{
	test();
	return 0;
}

以上就是C语言实现经典扫雷小游戏的示例代码的详细内容，更多关于C语言扫雷游戏的资料请关注我们其它相关文章！