I've got some images within a div
which i'm trying to when I click the next button animate to the next one in the div
In this div I also have my previous and next button which I obviously don't want to animate to.
<div class="work">
<a href="#" class="rightButton"><img src="http://www.jamietaylor-webdesign.co.uk/images/home/right.png" /></a>
<a href="#" class="leftButton"><img src="http://www.jamietaylor-webdes开发者_运维问答ign.co.uk/images/home/left.png" /></a>
<a href="#" class="1"><img class="topLeft" src="http://i.stack.imgur.com/JQFbb.jpg" /></a>
<a href="#" class="2"><img class="topRight" src="http://i.stack.imgur.com/l5OPs.jpg" /></a>
<a href="#" class="3"><img class="bottomLeft" src="http://i.stack.imgur.com/okxQz.jpg" /></a>
<a href="#" class="4"><img class="bottomRight" src="http://i.stack.imgur.com/4uPHw.jpg" /></a>
</div>
My jQuery which doesn't actually work
// prevent click jump
$('a').click(function() {
return false;
});
// do work
$('.work > .leftButton').click(function() {
//animate to previous image in the list
$(this).siblings().prev().show();
});
$('.work > .rightButton').click(function() {
//animate to next image in the list
$(this).siblings().next().show();
});
Is there a way to animate to the next image that doesn't have the class of leftButton
or rightButton
.
Also is there a way so that if i'm on the first image it will go to the last image in the div?
Here's a link to the jsFiddle i've got
Any ideas?
Edited to scroll images into view:
This requires some change to your markup, but will allow images to scroll left/right:
HTML:
<div class="work">
<div class="nav">
<a href="#" class="rightButton"><img src="http://www.jamietaylor-webdesign.co.uk/images/home/right.png" /></a>
<a href="#" class="leftButton"><img src="http://www.jamietaylor-webdesign.co.uk/images/home/left.png" /></a>
</div>
<div class="scroller">
<div class="items">
<a href="#" class="1"><img class="topLeft" src="http://i.stack.imgur.com/JQFbb.jpg" /></a>
<a href="#" class="2"><img class="topRight" src="http://i.stack.imgur.com/l5OPs.jpg" /></a>
<a href="#" class="3"><img class="bottomLeft" src="http://i.stack.imgur.com/okxQz.jpg" /></a>
<a href="#" class="4"><img class="bottomRight" src="http://i.stack.imgur.com/4uPHw.jpg" /></a>
</div>
</div>
</div>
Relevant CSS:
div.work { background-color: #ddd; height:240px; position: relative; width:300px; margin-left:10px}
div.items { position:relative; width: 1000em; height: 240px; }
div.scroller { overflow: hidden; width: 300px; height: 100%; }
JavaScript:
$('.work .leftButton').click(function() {
var $items = $(".items");
if ($items.position().left === 0) {
$items.css("left", "-300px");
$items.children("a:last").prependTo($items);
}
$(".items").animate({
left: "+=300px"
});
});
$('.work .rightButton').click(function() {
var $items = $(".items");
if ($items.position().left === -900) {
$items.css("left", "-600px");
$items.children("a:first").appendTo($items);
}
$(".items").animate({
left: "-=300px"
});
});
Basically what's going on is that there's a fixed viewport (scroller
) with hidden overflow that contains a really long div
(items
) containing all the images. The items
div is just animated on every click of the next/previous buttons.
The tricky part is moving the last element to the front and vice/versa when the end of the line of images is reached. This is determined by hardcoded values, but could probably be improved using an exact calculation.
Working example: http://jsfiddle.net/andrewwhitaker/6TLK2/3/
If you remove 'display:none' from the CSS (on img tags), here is the code that works with your markup and rotates images on right and left buttons:
<script type="text/javascript">
<!--
$(function() {
$("div.work >a:gt(2)").hide();
$(".rightButton").click(function () {
if ($("div.work >a:last").is(":visible"))
{
$("div.work >a:gt(1)").hide();
$("div.work >a:eq(2)").show();
} else {
$("div.work >a:visible:gt(1)").hide().next().show();
}
});
$(".leftButton").click(function () {
if ($("div.work >a:eq(2)").is(":visible"))
{
$("div.work >a:gt(1)").hide();
$("div.work >a:last").show();
} else {
$("div.work >a:visible:gt(1)").hide().prev().show();
}
});
});
//-->
</script>
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