I want to detect and remove high-ASCII characters like ®, ©, ™ from a String in Java. Is 开发者_运维问答there any open-source library that can do this?
If you need to remove all non-US-ASCII (i.e. outside 0x0-0x7F) characters, you can do something like this:
s = s.replaceAll("[^\\x00-\\x7f]", "");
If you need to filter many strings, it would be better to use a precompiled pattern:
private static final Pattern nonASCII = Pattern.compile("[^\\x00-\\x7f]");
...
s = nonASCII.matcher(s).replaceAll();
And if it's really performance-critical, perhaps Alex Nikolaenkov's suggestion would be better.
I think that you can easily filter your string by hand and check code of the particular character. If it fits your requirements then add it to a StringBuilder
and do toString()
to it in the end.
public static String filter(String str) {
StringBuilder filtered = new StringBuilder(str.length());
for (int i = 0; i < str.length(); i++) {
char current = str.charAt(i);
if (current >= 0x20 && current <= 0x7e) {
filtered.append(current);
}
}
return filtered.toString();
}
A nice way to do this is to use Google Guava CharMatcher:
String newString = CharMatcher.ASCII.retainFrom(string);
newString
will contain only the ASCII characters (code point < 128) from the original string.
This reads more naturally than a regular expression. Regular expressions can take more effort to understand for subsequent readers of your code.
I understand that you need to delete: ç,ã,Ã , but for everybody that need to convert ç,ã,Ã ---> c,a,A please have a look at this piece of code:
Example Code:
final String input = "Tĥïŝ ĩš â fůňķŷ Šťŕĭńġ";
System.out.println(
Normalizer
.normalize(input, Normalizer.Form.NFD)
.replaceAll("[^\\p{ASCII}]", "")
);
Output:
This is a funky String
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