This is one array
Array ( [0] => 1 [1] => 2 )
The associative array is
Array ( [0] => Array ( [id_1] => 3 [id_2] =&开发者_开发问答gt; 1 ) [1] => Array ( [id_3] => 5 [id_4] => 3 ) )
I want to compare these arrays and get an array containing the values that are not present in the associative array
The result should be array(3) and array(5,3)
$array1 = array(1,2);
$array2 = array(
array(
'id_1' => 3,
'id_2' => 1
),
array(
'id_3' => 5,
'id_4' => 3,
)
);
I'm not sure if I understand the question, if you want to compare each array individually:
foreach($array2 as $subarray) {
var_dump(array_diff($subarray, $array1));
}
returns:
array
'id_1' => int 3
array
'id_3' => int 5
'id_4' => int 3
Otherwise if you don't want to loop through and flatten the array (using an array_flatten function from the php doc comments of array_values)
http://www.php.net/manual/en/function.array-values.php#97715
function array_flatten($a,$f=array()){
if(!$a||!is_array($a))return '';
foreach($a as $k=>$v){
if(is_array($v))$f=array_flatten($v,$f);
else $f[$k]=$v;
}
return $f;
}
var_dump(
array_unique(
array_diff(
array_flatten($array2), $array1
)
)
);
returns:
array
'id_1' => int 3
'id_3' => int 5
'id_4' is not shown because it doesn't have a unique value. You can remove the keys with array_values()
or leave in 'id_4' by removing the array_unique()
from the code.
something like this, maybe?
$array_a = array(1, 2);
$array_b = array(array(1, 3), array(3, 1));
$result = array();
foreach($array_b as $key => $sub_array_b){
foreach($sub_array_b as $sub_key => $value){
if(!in_array($value, $array_a) && !in_array($value, $result)) array_push($result, $value);
}
}
EDIT: I typed this before you edited your question. You can still modify the code above so that it creates a different array for each subarray in your associative array.
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