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SQL Server Tree Query

开发者 https://www.devze.com 2023-02-10 23:11 出处:网络
I need some help is MS SQL Server Query. I’m not much of a DBA.I have an application with an Organization Table which is made up of a parent-child relationship:

I need some help is MS SQL Server Query. I’m not much of a DBA. I have an application with an Organization Table which is made up of a parent-child relationship:

CREATE TABLE [dbo].[Organizations](
    [OrgPK] [int] IDENTITY(1,1) NOT NUL开发者_高级运维L,
    [OrgParentFK] [int] NULL,
    [OrgName] [varchar](200) NOT NULL,
CONSTRAINT [PK__Organizations] PRIMARY KEY CLUSTERED

Sample data looks like this:

OrgPK,   OrgParentFK, OrgName
1,  0,  Corporate
2,  1,  Department A
3,  1,  Department B
4,  2,  Division 1
5,  2,  Division 2
6,  3,  Division 1
7,  6,  Section 1
8,  6,  Section 2

I'm trying to generate a query that returns an org path based on a given OrgPK. Example if given OrgPK = 7 the query would return 'Corporation/Department B/Division 1/Section 1'

If give OrgPk = 5 the return string would be 'Corporation/Department A/Division 2'

Thank you for your assistance.


WITH  OrganizationsH (OrgParentFK, OrgPK, OrgName, level, Label) AS
(
    SELECT OrgParentFK, OrgPK, OrgName, 0, CAST(OrgName AS VARCHAR(MAX)) As Label
    FROM Organizations
    WHERE OrgParentFK IS NULL
    UNION ALL
    SELECT o.OrgParentFK, o.OrgPK, o.OrgName, level + 1,  CAST(h.Label + '/' + o.OrgName  VARCHAR(MAX)) As Label
    FROM Organizations o JOIN OrganizationsH h ON o.OrgParentFK = h.OrgPK
)

SELECT OrgParentFK, OrgPK, OrgName, level, Label
FROM OrganizationsH
WHERE OrgPK = 5

h/t to marc_s


It can also be solved by creating a scalar valued function:

-- SELECT [dbo].[ListTree](5)
CREATE FUNCTION [dbo].[ListTree](@OrgPK int)
RETURNS varchar(max)
AS
BEGIN
    declare @Tree varchar(MAX)
    set @Tree = ''

    while(exists(select * from dbo.Organizations where OrgPK=@OrgPK))
    begin
        select  @Tree=OrgName+'/'+@Tree,
                @OrgPK=OrgParentFK
        from    dbo.Organizations
        where   OrgPK=@OrgPK

    end
    return  left(@Tree,len(@Tree)-1)
END
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