find d square no.?

int n=16;

for(i=0;i<=n;i+开发者_开发知识库+) {
  if(n/i==i) {
    printf("its a square no");

  }
  else
    printf("not a square no.");

i want to print one statement neither else statement nor if statement.... but output getting not a prime 3 time and prime no one time again...

help me

output for n=16 and n=15

---

In your code you would also to test that the remainder is 0:

((n/i==i) && (n%i==0))

EDIT

As Sjoerd pointed out, I was being particularly bone-headed and you may as well just test i*i==n as so:

bool perfect(int n)
{
    for (int i=1; i<=n; i++)
        if (i*i==n)
            return true;
    return false;
}

I realise that this is C++ but you get the picture!

---

Perhaps

int n=16;
for(i=0;1<=n;i++)

should be

float n=16.0;
for(float i=1.0;i<=n;i++)

i=1.0 as you shouldn't divide by zero

you could use found_square=1 when you are successful, and possibly use another if/else statement to print if n is a square, depending on the value of found_square.

also you may like to add a break command following your successful case. As soon as you succeed, there would be no need to continue within the for loop.