How to get the list of divisors of a given number?

So the function inputs a list, and a number. Then it should return the index of the list that the number is able to be divided by. If there is no numbers in the list it c开发者_运维问答an be divided by, then it should just return a blank list.

For example,

div([5,10,15,2,34],10)
[0,1,3]

Here is my coding:

def div(nlst, n):
    nlst = []
    for div in nlst:
        if n % nlst == 0:
        return nlst.index(div)
        else: []

What is wrong with my code?

---

There are a few issues in your code:

def div(nlst, n):
    nlst = [] # You are deleting the original list here!
    for div in nlst: # The list nlst is empty
        if n % nlst == 0: # Cannot use a list 'nlst' as an operand of the % operation.
        return nlst.index(div) # You are returning a single element here
        else: [] # This does nothing

This code will do the job:

def div(nlst, n):
    result = []
    for i, e in enumerate(nlst):
        if n % e == 0:
            result.append(i)
    return result

A more compact version:

def div(nlst, n):
    return [i for i, e in enumerate(nlst) if n % e == 0]

---

List comprehensions to the rescue:

def div(nlst, n):
    return [i for i,v in enumerate(nlst) if n % v == 0]

>>> div([5,10,15,2,34], 10)   
[0, 1, 3]