I want to delete the Startmenu\XXX
folder and Program Files\XXX
menu upon uninstall for the application.
Tried RMDir /r
but this does not w开发者_如何学Goork for me.
(Windows 7)
RMDir is the correct instruction, your path is probably wrong.
A common issue with startmenu removal is forgetting to use RequestExecutionLevel, see this page on the NSIS wiki
Process Monitor can help you detect path and privilege issues...
Occasionally Windows won't let you remove a folder when it's still in use. The solution is to mark the folder (and/or files) for deletion on next system reboot. For this, use the flag /REBOOTOK
For files:
Delete /REBOOTOK "<filename>"
For folders
RMDir /R /REBOOTOK directoryname
After next reboot, the files/folders will be removed.
See also: http://nsis.sourceforge.net/Reference/RMDir
Here's your solution: add "SetShellVarContext all"
http://nsis.sourceforge.net/Shortcuts_removal_fails_on_Windows_Vista
Example code:
OutFile Win7.exe
Name Win7
Section
SetShellVarContext all
CreateDirectory "$SMPROGRAMS\Win7 Testing"
CreateShortcut "$SMPROGRAMS\Win7 Testing\win7test.lnk" "$WINDIR\notepad.exe"
WriteUninstaller "$EXEDIR\uninst.exe"
SectionEnd
Section uninstall
SetShellVarContext all
Delete "$SMPROGRAMS\Win7 Testing\win7test.lnk"
RMDir "$SMPROGRAMS\Win7 Testing"
SectionEnd
-joedf
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