I have C# list with lot of similar name i want to count all individual similar word.
Example
Suppose list has these values
one,one,one,two,two,four,four,four
then i want to calculate like 开发者_开发知识库this
one 3
two 2
four 3
how can i calculate value like this from list.
I would split the string on comma, loop through all the results and add each word to a hashtable or dictionary with a value of one. If the word (key) is already present, then increment the value.
string[] values = "one,one,one,two,two,four,four,four".Split(',');
var counts = new Dictionary<string, int>();
foreach (string value in values) {
if (counts.ContainsKey(value))
counts[value] = counts[value] + 1;
else
counts.Add(value, 1);
}
Or, if you prefer, here is a LINQ solution
var counts = values.GroupBy<string, string, int>(k => k, e => 1)
.Select(f => new KeyValuePair<string, int>(f.Key, f.Sum()))
.ToDictionary(k => k.Key, e => e.Value);
Here is a solution based on Linq:
string s = "one,one,one,two,two,four,four,four";
List<string> list = s.Split(',').ToList();
Dictionary<string, int> dictionary = list.GroupBy(x => x)
.ToDictionary(x => x.Key, x => x.Count());
foreach (var kvp in dictionary)
Console.WriteLine("{0}: {1}", kvp.Key, kvp.Value);
Output:
one: 3
two: 2
four: 3
This solutions doesn't take advantage of the fact that the common values are consecutive. If this is always the case, a slightly faster solution could be written, but this is fine for short lists, or if the items can come in any order.
Dictionaty<string, int> listCount = new Dictionaty<string, int>();
for (int i = 0; i < yourList.Count; i++)
{
if(listCount.ContainsKey(yourList[i]))
listCount[yourList[i].Trim()] = listCount[yourList[i].Trim()] + 1;
else
listCount[yourList[i].Trim()] = 1;
}
For List, you could do the following (untested):
List<string> list = new List<string>()
{
"One",
"One",
"Two",
// etc
}
Dictionary<string, int> d = new Dictionary<string, int>();
foreach (string s in list)
{
if (d.ContainsKey(s))
d.Add(s, 1);
else
d[s]++;
}
The preferred (and cleaner) method is to do this using GroupBy and Count with Linq, but I don't have the type to type out the syntax at the moment.
Good luck!
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