preg_replace regular expression issue

I'm trying 开发者_JS百科to clean up a string.

I need to only allow

1. Uppercase/lower letters
2. numbers
3. spaces, tabs, carriage returns
4. these characters: _-+*()[]!#?.,;:'"<>

Everything else needs to go bye-bye. How do I go about this? I have this, which works for the upper/lower case letters, numbers, and spaces. But I dont know how to account for the tabs, carriage returns, or how to do the special characters?

$str = preg_replace('/[^a-z0-9 ]/i', '', $str);

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Try

$str = preg_replace('/[^\w\r\n\t+*()[\]!#?.\,;:\'"<> -]/', '', $str);

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\s - whitespace character (includes tabs and line breaks)
\r - carriage return
Use "\" character for special symobls.

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$str = 'sample|';
$result = !(bool)strlen(preg_replace('/^[a-z0-9A-Z\r\s:_-+*()[]!#?.,;:\>\<]*/', '', $str))