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as3: date.getMinutes > how to add zeros ? (05:09 AM = 5:9 AM)

开发者 https://www.devze.com 2023-02-10 04:32 出处:网络
How to fix date to retrieve minutes/hours with zeros ? e.g. it\'s 05:09 AM > trace(_date.getHours()+\":\"+_date.getMinutes());//5:9

How to fix date to retrieve minutes/hours with zeros ?

e.g. it's 05:09 AM >

trace(_date.getHours()+":"+_date.getMinutes());  //5:9

but i want 05:09 instead of 5:9 - so how t开发者_开发知识库o add zeros ??

    var _date = new Date();

    ...

    _min = _date.getMinutes();

    //fix date:
                var _str:String = _min.toFixed(1);
                _min = Number(_str);

    trace(_date.getHours()+":"+_date.getMinutes());

= 5:9 .... -_-

what's wrong ?


You can format it with something like:

minutes_txt:String = _date.getMinutes() < 10 ? "0" + _date.getMinutes() : _date.getMinutes();

which will pad a zero if the minutes is less than 10, and then just trace that instead of only _date.getMinutes


Personally, I would write a more generic routine. I've done it two ways:

More traditional approach:

    // Pass in 'value' you want to pad, and 'len' as total length of string 
    // to be returned to you. For example, value=24, len=6 would return 000024.
    public static function padIntWithLeadingZeros2(value:int, len:uint):String
    {
        var paddedValue:String  = value.toString();

        if (paddedValue.length < len)
        {
            for (var i:int = 0, numOfZeros:int = (len - paddedValue.length); i < numOfZeros; i++)
            {
                paddedValue = "0" + paddedValue;
            }
        }

        return paddedValue;
    }   

My own style of doing it:

    // Pass in 'value' you want to pad, and 'len' as total length of string 
    // to be returned to you. For example, value=24, len=6 would return 000024.
    public static function padIntWithLeadingZeros(value:int, len:uint):String
    {
        var paddedValue:String  = value.toString();

        if (paddedValue.length < len)
        {
            var leadingZeros:String = "0000000000";
            paddedValue = leadingZeros.substring(0, (len - paddedValue.length)) + paddedValue;
        }

        return paddedValue;
    }

Turns out that one is as efficient as the other in terms of lapsed time to execute the function. So, it's just a matter of preference.

R. Grimes

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