python mongodb regex: ignore case

How can I specify a REGEX and ignore the case:

regex = ".*" + filter + ".*";
config.gThingCollection.find({"name":{开发者_StackOverflow中文版"$regex":regex}})

I want the filter to be case-insensitive, how to achieve that?

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Try using the python regex objects instead. Pymongo will serialize them properly:

import re
config.gThingCollection.find({"name": re.compile(regex, re.IGNORECASE)})

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You can use MongoDB regex options in your query.

config.gThingCollection.find({"name":{"$regex":regex, "$options": "-i"}})

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res = posts.find({"geography": {"$regex": 'europe', "$options": 'i'}})

# if you need use $not
import re
res = posts.find(
    {"geography": {"$not": re.compile('europe'), "$options": 'i'}})

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Your code should look like this:

regex = ".*" + filter + ".*";
config.gThingCollection.find({"name":{"$regex":regex, "$options":"i"}})

Reference: http://docs.mongodb.org/v2.2/reference/operator/regex/