I have some开发者_JAVA百科 stuff I want to perform in .bashrc which I would prefer to exist in another file on the system. How can I include this file into .bashrc?
Add source /whatever/file
(or . /whatever/file
) into .bashrc
where you want the other file included.
To prevent errors you need to first check to make sure the file exists. Then source the file. Do something like this.
# include .bashrc if it exists
if [ -f $HOME/.bashrc_aliases ]; then
. $HOME/.bashrc_aliases
fi
Here is a one liner!
[ -f $HOME/.bashrc_aliases ] && . $HOME/.bashrc_aliases
Fun fact: shell (and most other languages) are lazy. If there are a series of conditions joined by a conjunction (aka "and" aka &&
) then evaluation will begin from the left to the right. The moment one of the conditions is false, the rest of the expressions won't be evaluated, effectively "short circuiting" other expressions.
Thus, you can put a command you want to execute on the right of a conditional, it won't execute unless every condition on the left is evaluated as "true."
If you have multiple files you want to load that may or may not exist, you can keep it somewhat elegant by using a for loop.
files=(somefile1 somefile2)
path="$HOME/path/to/dir/containing/files/"
for file in ${files[@]}
do
file_to_load=$path$file
if [ -f "$file_to_load" ];
then
. $file_to_load
echo "loaded $file_to_load"
fi
done
The output would look like:
$ . ~/.bashrc
loaded $HOME/path/to/dir/containing/files/somefile1
loaded $HOME/path/to/dir/containing/files/somefile2
I prefer to check version first and assign variable for path config:
if [ -n "${BASH_VERSION}" ]; then
filepath="${HOME}/ls_colors/monokai.sh"
if [ -f "$filepath" ]; then
source "$filepath"
fi
fi
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