I don't understand what's happening 开发者_JS百科here. Logically, it doesn't make any sense to me.
<?php
$level = 0;
switch ($level) {
case $level > 80: $answer = 'high'; break;
case $level > 60: $answer = 'moderate-to-high'; break;
case $level > 40: $answer = 'moderate'; break;
case $level > 20: $answer = 'low-to-moderate'; break;
default: $answer = 'low'; break;
}
echo $answer;
?>
When $level == 0, it returns "high". This doesn't make any sense to me. Can someone explain what's happening here?
Change switch ($level)
to switch (true)
and this will work.
switch
statements perform equality tests on the values in the cases. PHP is evaluating your >
comparisons, so case $level > 80
becomes case false
. false
is considered to be equal to 0
, so the first case matches.
The quantity after the case
needs to be just the value, not a boolean expression. I'm guessing that PHP is evaluating case $level > 80
as case ($level > 80)
which is becoming case 0
(i.e., false, since $level
is indeed NOT less than 80) and so you're matching the first case.
Are you sure you can do this in php?
I just checked the manual of switch and you have to provide a distinct value.
I think if you can write it again into something like:
$levelDivTwenty = intval($level/20);
$levelDivTwenty = ($levelDivTwenty>4)?4:$levelDivTwenty;
and then case on that.
switch ($levelDivTwenty) {
case 4: //same as $level > 80 before...
case 3: //>60 etc...
}
As others have pointed out you can't use switch like that, but how about defining it like this:
<?
$level = 21;
$answers = array('low', 'low-to-moderate',
'moderate', 'moderate-to-high', 'high');
echo $answers[intval(($level-1)/20)];
?>
Note: If $level = 0, then expression inside intval() will be -1/20, which is less then -1 and therefore will be rounded to 0.
This isn't really how switch is intended to be used. It's to evaluate for a specific value.
Use an If/else if here, instead of complicating your life to make a switch work like one.
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