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Regular Expression - How to find a match within a match?

开发者 https://www.devze.com 2023-02-09 08:45 出处:网络
I\'ve been tr开发者_JAVA技巧ying to do the following using VBs Regular Expression object but could not find an easy way to do it. Is there anyone who could provide some suggestions?

I've been tr开发者_JAVA技巧ying to do the following using VBs Regular Expression object but could not find an easy way to do it. Is there anyone who could provide some suggestions?

For example, I have a string "12<56>89", I would like to get the string inside the "<>" which should be "56" in this case. What I'm currently doing is I try to find the expression "<\d+>" which will return <56>. Then I try to find the expression "\d+" from the result of the first match which will return 56.

I don't like this way because it needs to call the function twice. I'm wondering if it's possible to get the string inside the "<>" using just one regular expression? Thank you!

Thanks, Allen


Use the expression "<(\d+)>"

You can then access all matches as a collection. Your regex can match more than once if you set RegEx.Global = True. The first match is found in var(0), second at var(1). Submatch groups are found at var(0).SubMatches(0), etc. If you're only doing it once, you can one line it:

Dim RegEx : Set RegEx = New RegExp
RegEx.Pattern = "<(\d+)>"
Dim strTemp : strTemp = "12<56>89"
WScript.Echo RegEx.Execute(strTemp)(0).SubMatches(0)

Test out your regular expressions here: http://www.regular-expressions.info/vbscriptexample.html


Use the expression <(\d+)>. Execute the regular expression using

Set matches = expr.Execute(text)
If matches.Count > 0 Then
    result = matches(0).Submatches(0)
End If

The Submatches collection contains strings that correspond to the parenthesis groupings in the expression.

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