I am recording site usage events in a sub object of a (visitor). here is a basic example of the data structure:
{ "_id" : ObjectId("4d4c695794b332a0740009bd"), "evs" : [
{
"ev" : "Visit Home Page",
"d" : 1,
"s" : 1
},
{
"ev" : "Buy Product",
"d" : "110.10",
"upc" : 1234,
"s" : 1
},
{
"ev" : "Sign up to newsletter",
"d" : "1",
"s" : 1
}
]}
I have an index on 'evs.s', but when I search on evs.s, the index is not used:
db.visitors.find({'evs.s':0}).explain()
{
"cursor" : "BtreeCursor evs.s_1",
"nscanned" : 33361,
"nscannedObjects" : 33361,
"n" : 33361,
"millis" : 311,
"nYields" : 105,
"nChunkSkips" : 0,
"isMultiKey" : false,
"indexOnly" : false,
"indexBounds" : {
"evs.s" : [
[
0,
0
]
]
}
}
That query takes 311 milliseconds and scans through every object.
Here is the index: db.visitors.getIndexes()
{
"ns" : "tracking.visitors",
"unique" : false,
"key" : {
"evs.s" : 1
},
"name" : "evs.s_1",
"v" : 0
}开发者_开发问答
Your query actually is using an index, as indicated by the cursor type in the explain output ("BtreeCursor evs.s_1"). If you were not using a an index, it would be "BasicCursor".
From your input data, it looks like evs.s might not be a very efficient key to index on. If all of the values of evs.s are either 1 or 0, your index will always hit a large number of matches.
My guess is that your query did not do a full table scan, but that there are actually that many records with a value of evs.s = 0 in your index.
You might compare the output of
db.visits.find({evs.s: 0}).count();
db.visits.find({evs.s: 1}).count();
db.visits.find().count();
to verify this.
There are several things you can do to speed this up:
1) You can use a different index that has more distinct values. This will reduce the search space on each query.
2) You can add a limit statement to your query. This will stop scanning the index once limit documents have been found.
"cursor" : "BtreeCursor evs.s_1"
means that the index is used.
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