I reduced a debugging problem in Mathematica 8 to something similar to the following code:
f = Function[x,
list = {1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5};
Count[list, x]
];
f[4]
Maximize{f[x], x, Integers]
Output:
4
{0, {x->0}}
So, while the maximum o function f is obtained when x equals 4 (开发者_如何转开发as confirmed in the first output line), why does Maximize return x->0 (output line 2)?
The reason for this behavior can be easily found using Trace
. What happens is that your function is evaluated inside Maximize with still symbolic x
, and since your list does not contain symbol x
, results in zero. Effectively, you call Maximize[0,x,Integers]
, hence the result. One thing you can do is to protect the function from immediate evaluation by using pattern-defined function with a restrictive pattern, like this for example:
Clear[ff];
ff[x_?IntegerQ] :=
With[{list = {1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5}}, Count[list, x]]
It appears that Maximize
can not easily deal with it however, but NMaximize
can:
In[73]:= NMaximize[{ff[x], Element[x, Integers]}, x]
Out[73]= {4., {x -> 4}}
But, generally, either of the Maximize
family functions seem not quite appropriate for the job. You may be better off by explicitly computing the maximum, for example like this:
In[78]:= list = {1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5};
Extract[#, Position[#, Max[#], 1, 1] &[#[[All, 2]]]] &[Tally[list]]
Out[79]= {{4, 4}}
HTH
Try this:
list = {1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5};
First@Sort[Tally[list], #1[[2]] > #2[[2]] &]
Output:
{4, 4}
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