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Can't use success error function in $.when()

开发者 https://www.devze.com 2023-02-08 05:06 出处:网络
I am using jQuery 1.5 function doAjax(){ return $.get(\'ajax.php\'); } function doMoreAjax(){ return $.get(\'ajax.php\');

I am using jQuery 1.5

function doAjax(){
    return $.get('ajax.php');
}

function doMoreAjax(){
   return $.get('ajax.php');
}

$.when( doAjax(), doMoreAjax() ).then(function(){
     console.log( 'I fire once BOTH ajax requests have completed!' );
}).fail(function(){
   console.log( 'I fire if one or more requests failed.' );
}).success(function(){
    console.log( 'I fire if all requests success.' ); //It not works for me
})

Question: I can't use success and error function with $.when since $.when or $.ajax are same.

I c开发者_JS百科an use success and error with $.ajax why I can't use with $.when


I think you got a wrong idea about it.

from the docs,

$.when(doAjax(), doMoreAjax())
  .then(myFunc, myFailure);
// Execute the function myFunc when both ajax requests are successful, 
// or myFailure if either one has an error.

and you might wanna read Deffered Object. I know you would get this kind of error in the console, Uncaught TypeError: Object #<an Object> has no method 'success', simply because .then() returns a Deffered Object.

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