Can I implement an interface that contains a property that is of child type to what is required by the interface?

I am receiving the following error:

ClassName.PropertyName cannot implement IClassType.PropertyName because it does not have the matching return type of IBasePropertyType

No开发者_高级运维w, for the code:

public class ClassName : IClassType
{
    public IChildPropertyType PropertyName { get; set; }
}

public interface IClassType
{
    public IBasePropertyType PropertyName { get; set; }
}

public interface IBasePropertyType
{
    // some methods
}

public interface IChildPropertyType : IBasePropertyType
{
    // some methods
}

Is there a way to do what I am attempting? I know that the issue is with co/contravariance, but I can't seem to figure out how to do this.

---

In order to implement the given interface, you must have the same return type. However, there are a couple of potential work-arounds to make life easier:

1. make your interface generic
2. implement the interface explicitly.

If you make IClassType generic, like so:

public interface IClassType<T> where T : IBasePropertyType
{
    public T PropertyName { get; set; }
}

... then you can implement this interface using various property types:

public class ClassName : IClassType<IChildPropertyType>
{
    public IChildPropertyType PropertyName { get; set; }
}

Another option would be to leave your interface non-generic, but to have a generic base type that explicitly implements the interface:

public class ClassBase<T> : IClassType
    where T : IChildPropertyType
{
    IBasePropertyType IClassType.PropertyName { 
        get {return PropertyName;}
        set {PropertyName = (IChildPropertyType)value;}
    }
    T PropertyName {get;set;}
}

Note that this last option is not quite ideal because you must dynamically cast the property to the given child type: while you can guarantee that every IChildProperty type is an IBasePropertyType, you cannot guarantee that every IBasePropertyType is an IChildPropertyType. However, if you can eliminate the setter from the original interface, or if you can take other steps to guarantee that the setter will never be called with the wrong type in your code, then this could work.

---

You are correct that this has to do with covariance; specifically it has to do with virtual method return type covariance, which is not a kind of covariance that the C# language supports.

---

UPDATE: This answer is over ten years old. C# may soon implement return type covariance. Please see https://github.com/dotnet/csharplang/issues/49 for details.

---

Note that even if it did, the system you describe is not type safe. Suppose we have:

interface IAnimal {}
interface IGiraffe : IAnimal {}
interface ITiger: IAnimal {}
class Tiger : ITiger {}
interface IHaveAnAnimal { IAnimal Animal { get; set; } }
class C : IHaveAnAnimal
{
    public IGiraffe Animal { get; set; }
}
...
IHaveAnAnimal x = new C();
x.Animal = new Tiger(); // Uh oh. We just put a Tiger into a property of type IGiraffe.

Even if the covariance were legal at all, this kind of covariance would not be legal; you'd have to have no setter for the covariance to be legal.

Suppose then you did have no setter:

interface IAnimal {}
interface IGiraffe : IAnimal {}
interface ITiger: IAnimal {}
class Tiger : ITiger {}
interface IHaveAnAnimal { IAnimal Animal { get; } }
class C : IHaveAnAnimal
{
    public IGiraffe Animal { get; }
}

Unfortunately this is still not legal. But you can do this:

class C : IHaveAnAnimal
{
    IAnimal IHaveAnAnimal.Animal { get { return this.Animal; } }
    public IGiraffe Animal { get; }
}

Now when C is used as a C, Animal returns a giraffe, and when used an an IHaveAnAnimal, it returns an IAnimal.