Do I do something wrong? I need the youtube code, but it doesn't return the real value.
if(preg_match_all("http:\/\/www\.youtube\.com\/v\/(.*)(.*)", $row->n_texto, $matches){
$code = $image_to_thumb .= "http://i1.ytimg.com/vi/".$matches[1][0]."/0.jpg";
}
Edit - ircmaxell Based on the comment,开发者_运维问答 the link structure in the text is:
http:// www.youtube.com/v/plMvAh10HVg%26hl=en%26fs=1%26rel=0
Update
The problem is: my code return a link like this:
http://www.youtube.com/v/plMvAh10HVg%26hl=en%26fs=1%26rel=0
Can I stop it with regexp before appear %26hl=en%26fs=1%26rel=0
?
Your regex is not correct. There are more than a few things wrong with it. Now, as far as what you want, try this:
#http://(?:.*)youtube.com/v/([^/\#?]+)#
Now, as for why, let's look at the regex:
http://(?:.*)youtube.com
You're looking for a string that starts with http://
, has anything after (www.
, ww2.
, or nothing).
/v/
You're looking for /v/
as the start of the URL.
([^/\\#?]+)
You're looking for everything else UP TO another /
, a query string (?
) or a anchor (#
). So that should match the ID you're looking for.
So, it would be
if(preg_match("#http://(?:.*)youtube.com/v/([^/\#?]+)#", $row->n_texto, $matches){
$code = $image_to_thumb .= "http://i1.ytimg.com/vi/".$matches[1]."/0.jpg";
}
If you wanted to find all:
if(preg_match_all("#http://(?:.*)youtube.com/v/([^/\#?]+)#", $row->n_texto, $matches){
foreach ($matches[1] as $match) {
$code = $image_to_thumb .= "http://i1.ytimg.com/vi/".$match."/0.jpg";
}
}
the link provided has a space before the 1st w in www.youtube.com, the code you need is :
if(preg_match_all("%http://www\.youtube\.com/v/([\w]+)%i", $row->n_texto , $matches)){
$code = $image_to_thumb .= "http://i1.ytimg.com/vi/".$matches[1][0]."/0.jpg";
}
also, the url you have is encoded, you may want to use urldecode($row->n_texto) before using it.
^http://\w{0,3}.?youtube+\.\w{2,3}/watch\?v=[\w-]{11}
according to http://www.regexlib.com/REDetails.aspx?regexp_id=2569
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