Is it possible to use imagecreatefrompng() with a php file that returns a dynamic png image?
eg.
<?php
$IM = imagecreatefrompng('image.php?var=1');
?>
where image.php looks something like:
开发者_StackOverflow中文版<?php
// code to generate image
header("content-type: image/png");
imagepng ( $OUTPUT );
?>
At the moment I'm getting a "failed to open stream" error - can this be done? If not, are there any quick & easy workarounds? (that don't involve using image.php to save a .png file for the script to detect instead.)
Thanks,
Chris
Query parameters ?var=1
work only when requesting a resource through http, not through the file system. To do this, you would have to specify a full URL:
<?php
$IM = imagecreatefrompng('http://localhost/image.php?var=1');
?>
(If your PHP is configured to allow this)
However, the usually much more desirable way would be to include image.php
directly and pass var
to it using a normal variable. That saves you a http request that, even if made locally, spawns a new PHP process.
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