I have a table, and usually i use this selector to apply odd and even row:
table.find('tbody tr:even').addClass('even');
table.find('tbody tr:odd').removeClass('even');
My Table has rows being inserted at various places, hence why i remove it from the odd rows.
I now have certain ro开发者_如何转开发ws hidden using
jQueryTrObject.hide();
I want to apply the same styling as before, so that alternate rows, as far as the user is concerned are marked up odd and even, and i'd like it to take into account of hidden rows.
How do i write a selector to do this, for do i have to use the each and specifically check?
use the :visible
selector
table.find('tbody tr.even').removeClass('even');
table.find('tbody tr:visible:even').addClass('even');
Remember to use it first so that the :even
filter applies after it.
Try this out:
table.find('tbody tr').removeClass('even')
.filter(':visible:even').addClass('even');
Use a :not(:hidden)
selector
table.find('tbody tr:not(:hidden):even').addClass('even');
You can use the :visible selector to only markup visible row:
table
.find('tbody tr:visible:even')
.addClass('even')
.end()
.find('tbody tr:visible:odd')
.removeClass('even');
.end();
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