I'm trying to initialize a private variable of my Class passing a const string &aString to it as parameter.
Here's my method:
void Image::initWithTextureFile(const std::string &inTextureName)
{
Texture2D *imTexture = TEXTURE_MANAGER->createTexture(inTextureName);
if(imTexture)
{
开发者_JAVA百科 texture = imTexture;
scale = 1.0f;
name = inTextureName; //name is a private string variable inside my class
initImplementation();
}else {
printf("Could not load texture when creating Image from file %s\n",inTextureName.c_str());
}
}
My problem is the following, when I call this method I do it like:
myInitializer.initWithTextureFile("myFile.bmp");
When I'm inside the scope of initWithTextureFile
the name
variable takes the value of inTextureName
. For this example if I cout << name << endl;
inside initWithTextureFile
i would get "myFile.bmp"
But when I leave the scope of the function, name
looses it's value, so when i cout << name << endl;
I get nothing printed in the console.
Could anyone point me out to what's going on here?
Name is declared:
private:
std::string name;
If you're outside the class scope, and cout << name
compiles at all, it means you have another variable named name
, and that's what's being picked up. If you want to refer to it outside the class, you'll have to come up with a way that will export it. You might, for example, have a member function like const std::string &GetName() { return name; }
.
You either omitting something in your description or are not showing appropriate code that could help solve your problem.
This works:
#include <iostream>
#include <string>
using namespace std;
struct A
{
void f(const string& str) { name = str; }
void g() { cout << name << endl; }
string name;
};
int main()
{
A a;
a.f("test");
a.g();
}
Output:
test
That should work. Are you sure it is not being modified somewhere else, such as in initImplementation?
The problem probably have to do with the name variable : is it a pointer or ref to string instead of a plain string ?
The only reasonable explanation here is that you must be working with two different name
objects. The one you declared as a class member should hold its value when you exit the method. It is just that outside the class method you must be printing a completely different name
, which is empty.
I was going to say something about short-lived stack objects but I realised that was wrong. What it could be is something to do with exporting the containing class from a DLL.
If so, you might find a warning like this:
c:\yourclass.h(7): warning C4251: 'YourClass::name_' : class 'std::basic_string<_Elem,_Traits,_Ax>' needs to have dll-interface to be used by clients of class 'YourClass'
This thread describes more.
How is 'name' declared? It seems like maybe it's declared as a reference instead of an object.
Try:
name = std::string(inTextureName);
精彩评论