开发者

Javascript - if statement not working?

开发者 https://www.devze.com 2022-12-12 01:52 出处:网络
I\'m trying to set a class to active depending on the url.I\'m trying to use the code below, but in every case, it activates the active class for the second tab.

I'm trying to set a class to active depending on the url. I'm trying to use the code below, but in every case, it activates the active class for the second tab.

var pathname = window.location.pathname;

if(pathname = '/learn/subsection2') {
            $("ul.tabs li:eq(1)").addClass("active").show(); //Activate second tab
            $(".tab_content:eq(1)").show(); //Show second tab 开发者_开发知识库content
    } else {
            $("ul.tabs li:first").addClass("active").show(); //Activate first tab
            $(".tab_content:first").show(); //Show first tab content
    }


You are assigning rather than checking for equality in your if statement.

if(pathname == '/learn/subsection2') {
...


if(pathname = '/learn/subsection2') { // assignment
if(pathname == '/learn/subsection2') { // test for equality
if(pathname === '/learn/subsection2') { // test for equality without type coercion


You're using = instead of ==, a common programming error. = is assignment, == is comparison.

if (pathname == '/lean/subsection2') { // ...

When using =, it assigns the string /lean/subsection2 to the variable pathname and evaluates it as a boolean value, which is always true (it'd have to be false or undefined), so it always takes the positive condition block.


Use == instead of = in the if statement.


You used a = instead of a == or === in your comparison. This is why many programmers shift the statement around so it throws an error vs. running code unintentionally... its a very common mistake!

Here is an example of the same ifg statement switched around. Had you used this format, but made the same mistake, it would have thrown an error which would have helped you located it faster:

if('/learn/subsection2' == pathname){ ... }
0

精彩评论

暂无评论...
验证码 换一张
取 消