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Matlab contourf

开发者 https://www.devze.com 2023-02-07 15:11 出处:网络
If I\'m asked to plot a function S with \"level lines\" abs(S) = 0:0.1:1, how do I do that? I looked up the solution:

If I'm asked to plot a function S with "level lines" abs(S) = 0:0.1:1, how do I do that?

I looked up the solution:

  [X,Y] = meshgrid(-15:0.1:15);
  Z = X + i*Y;
  contourf(X,Y,abs(S),[1 1]);

where they pass in the fourth开发者_运维知识库 argument [1 1] but I've no idea what it's doing. Why do they pass in [1 1] if they ask me for lines between 0 and 1?

Any help is much appreciated!


They're making a mistake.

The help to contourf states

To draw a single contour of level i, use contour(Z,[i i])

So they're drawing a single contour line at 1.

You want to write

contourf(X,Y,abs(S),0:0.1:1);

because the help says

contourf(Z,v) draws a filled contour plot of matrix Z with contour lines at the data values specified in the monotonically increasing vector v. The number of contour levels is equal to length(v)

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