this might be quite simple I'm just not seeing the wood for the trees at the moment. In Oracle I'm selecting records from table A that joins to table B based on the primary key of table A. However table B can have multiple records matching the primary key of table A. This is causing my query to 开发者_如何转开发return duplicate rows from table A. Below is a cut down version of my query:
TableA TableB
_______ _________
1, Sec1 2, 11/01/2011
2, Sec2 2
3, Sec3 5, 10/01/2011
4, Sec4 6, 10/01/2011
Select A.SecID, A.SecName, B.DateSent from tableA A
inner join tableB B on A.SecID = B.SecID
This is returning 2 records for Sec2 - how can I get it to return only 1 record for Sec2? I've tried using distinct and unique but still get the same results.
SELECT secid, secname
FROM tableA
WHERE secid IN
(
SELECT secid
FROM tableb
)
If you need a record from tableB
as well:
SELECT secid, secname, datesent
FROM (
SELECT a.secid, a.secname, b.datesent, ROW_NUMBER() OVER (PARTITION BY a.secid ORDER BY b.datesent DESC) AS rn
FROM tableA a
JOIN tableB b
ON b.secid = a.secid
)
WHERE rn = 1
ORDER BY
clause controls which of the multiple records on b
will you get.
You can use a GROUP function to select only one row:
SELECT A.SecID, A.SecName, max(B.DateSent) DateSent
FROM tableA A
JOIN tableB B on A.SecID = B.SecID
GROUP BY A.SecID, A.SecName
SELECT DISTINCT a.secid, a.secname
FROM tableA a, tableB b
WHERE a.secid = b.secid;
The solutions suggested are very good. There are cases when you may have take a bit different approach specially when one of the tables is very large compared to another one and absence of an index on foreign key column in table B.
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