Extracting an integer from a line with the help of linux script?

I have a file, one of whose line contains:

number 8

how can i use sed, grep or whatever linux script to find out what intege开发者_如何转开发r is there in front of the line that starts with "number"?

Thanks...

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awk '$1=="number"{print $2}' file

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Use awk:

cat ./file.text | awk '/number/ {print $2}'

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use grep and cut, this will return only the number

cat ./file.txt | grep number | cut -d " " -f 2

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Another way is to use awk:

awk '/number/ {print $2}' < ./file.txt

It's a single command, which some prefer. If it's a large file, you may prefer the cat | grep | cut-way, as the three programs run in separate processes.