Why does this compile command sequence keep creating a 64 bit file?

I'm using a mac OSX and trying to compile a binary from source.

the commands I'm using are

 /Applications/MAMP/bin/php5.3/bin/phpize CFLAG开发者_JAVA百科S='-O2 -arch i386 -arch ppc -g -Os' LDFLAGS='-O2 -arch i386 -arch ppc ' CXXFLAGS='-O2 -arch i386 -arch ppc -g -Os' 
  ./configure --disable-dependancy-tracking --disable-shared -enable-static
  make
  make install

I've previously tried also including a number of other flags

-arch x86_64

and

 --with-php-config="/Applications/MAMP/bin/php5.3/bin/php-config"

but every time I check the compiled file it tells me that it's an x86_64 bundle.

What am I missing?

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Try adding -m32 to the flags. I doubt the optimization flags are making a difference here.

From the manual for gcc:

   -m32
   -m64

Generate code for a 32-bit or 64-bit environment. The 32-bit environment sets int, long and pointer to 32 bits and generates code that runs on any i386 system. The 64-bit environment sets int to 32 bits and long and pointer to 64 bits and generates code for AMD's x86-64 architecture. For darwin only the -m64 option turns off the -fno-pic and -mdynamic-no-pic options.

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Random guess, possibly not correct. Try setting CC instead.

CC="gcc -m32"

Edit:

Reason for my suggestion is that I don't know if CFLAGS is always respected in your build.

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After configuring, I edited the Makefile and changed the following:

CC = cc to CC = cc -m32

And voila.