I am using following code,
- (void)application:(UIApplication *)application didRecei开发者_运维问答veRemoteNotification:(NSDictionary *)userInfo {
//code here to handle call
//[[UIApplication sharedApplication] openURL:
// [NSURL URLWithString:@"tel:1-408-555-5555"]];
UIAlertView *alert1=[[UIAlertView alloc]initWithTitle:@"Teshjhjkhhjkhjkhjkhkjhkhkhkjhjkhjkkkjhjhhjhjkjt" message:@"Test" delegate:self cancelButtonTitle:@"ok" otherButtonTitles:nil];
[alert1 show];
[alert1 release];
}
but when application is open I can see the alert, but I want this alert when I press the view button in push message.
Try to implement in this format:
- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo {
application.applicationIconBadgeNumber = 0;
self.textView.text = [userInfo description];
// We can determine whether an application is launched as a result of the user tapping the action
// button or whether the notification was delivered to the already-running application by examining
// the application state.
if (application.applicationState == UIApplicationStateActive)
{
// Nothing to do if applicationState is Inactive, the iOS already displayed an alert view.
UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Did receive a Remote Notification"
message:[NSString stringWithFormat:@"The application received this remote notification while it was running:\n%@",
[[userInfo objectForKey:@"aps"] objectForKey:@"alert"]]
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alertView show];
[alertView release];
}
}
精彩评论