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Use JavaScript Returned Values in jQuery

开发者 https://www.devze.com 2023-02-06 18:54 出处:网络
Hey Guys. So this is more about me not knowing JS than being a real hard question. I\'m trying to write a little function in JS that I can call from jQuery to resize an i开发者_C百科mage. The thing i

Hey Guys. So this is more about me not knowing JS than being a real hard question.

I'm trying to write a little function in JS that I can call from jQuery to resize an i开发者_C百科mage. The thing is I have no idea how to return the values back to jQuery after the JS function runs. Here is what i have so far:

$('a').click(function() {
    var slideshowHeight = $(this).closest('.stage').css('height')
    var slideshowWidth = $(this).closest('.stage').css('width')
    var newImageHeight = $(this).attr('data-height')
    var newImageWidth = $(this).attr('data-width')

    fit_within_box(slideshowWidth, slideshowHeight, newImageWidth, newImageHeight);

    $(this).children('img').css('width',new_width);
    $(this).children('img').css('width',new_height);
}

function fit_within_box(box_width, box_height, width, height)
{
    var new_width = width
    var new_height = height
    var aspect_ratio = parseInt(width) / parseInt(height)

    if (new_width > box_width)
    {
        new_width = box_width
        new_height = int(new_width / aspect_ratio)
    }

    if (new_height > box_height)
    {
        new_height = box_height
        new_width = int(new_height * aspect_ratio)
    }
    return (new_width, new_height)
}

As you can see, I'm trying to feed in some values and get back new_width and new_height.

Thanks for the help!


If you want to return both values at once, you could do it with an object literal...

return {
   width: new_width,
   height: new_height
};


you can try to return a JSON object like this:

return {
    new_height:height,
    new_width:width
};

and use it in your jquery function:

var fit_img = fit_within_box(...);
...
$(this).children('img').css('height',fit_img.new_height);


Hey, here's the working example, I've fixed some small mistakes e.g. you've used width twice on children('img');

jQuery:

$(function(){
    $('a').click(function() {
        var slideshowHeight=$(this).closest('.stage').height();
        var slideshowWidth=$(this).closest('.stage').width();
        var newImageHeight=$(this).attr('data-height');
        var newImageWidth=$(this).attr('data-width');
        var size=fit_within_box(slideshowWidth,slideshowHeight,newImageWidth,newImageHeight);
        $(this).children('img').css({'width':size[0],'height':size[1]});
    });

    function fit_within_box(box_width,box_height,new_width,new_height){
        var aspect_ratio=new_width/new_height;
        if(new_width>box_width){
            new_width=box_width;
            new_height=Math.round(new_width/aspect_ratio);
        }
        if(new_height>box_height){
            new_height=box_height;
            new_width=Math.round(new_height*aspect_ratio);
        }
        return [new_width,new_height];
    }
});

HTML with some wallpaper:

<div class="stage" style="width:200px;height:200px;">
<a href="#" data-width="1280" data-height="1024"><img src="wallpaper_1280x1024.jpg" /></a>
</div>

Cheers

G.

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