Displaying Hexadecimal numbers

We would display Hexadecimals in A03Eh format which A=10 & 开发者_C百科E=14, and A is a nibble. But I have seen another display like this : 0x002314A8 , How can we convert the above number into this format ? what is this format ?

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int a = 0x002314A8;
printf("a = 0x%08X", a);

or

std::out << "a = 0x" << std::hex << std::uppercase << std::setfill('0') << std::setw(8) << std::setprecision(8) << a ;

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The format 0x is the standard Unix way of representing hexadecimal numbers. I am used to seeing 0x at the beginning and not h at the end.

That is the only difference. Like Péter Török said, if you're using C/C++ there are ways to modify what is shown when you print.

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Write a function that takes an integer and returns a string in that format. Then call it like this:

std::cout << toHex(0xA03E);

It shouldn't be that difficult a function to write. Using the ios::hex manipulator will display your number in the 0x format. Is that what you wanted?