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Split string on a number, preserving the number

开发者 https://www.devze.com 2023-02-06 16:32 出处:网络
I have a string which will alway开发者_JAVA百科s be at least a number, but can also contain letters before and/or after the number:

I have a string which will alway开发者_JAVA百科s be at least a number, but can also contain letters before and/or after the number:

"4"
"Section 2"
"4 Section"
"Section 5 Aisle"

I need to split the string like this:

"4" becomes "4"
"Section 2" becomes "Section ","2"
"4 Aisle" becomes "4"," Aisle"
"Section 5 Aisle" becomes "Section ","5"," Aisle"

How can I do this with Ruby 1.9.2?


String#split will keep any groups from the delimiter regexp in the result array.

parts = whole.split(/(\d+)/)


In case you didn't really want the whitespace in the separators, and you did want to have a consistent handle on the before/after, use this:

test = [
  "4",
  "Section 2",
  "4 Section",
  "Section 5 Aisle",
]

require 'pp'
pp test.map{ |str| str.split(/\s*(\d+)\s*/,-1) }
#=> [["", "4", ""],
#=>  ["Section", "2", ""],
#=>  ["", "4", "Section"],
#=>  ["Section", "5", "Aisle"]]

Thus you could always do:

prefix, digits, suffix = str.split(/\s*(\d+)\s*/,-1)
if prefix.empty?
  ...
end

...instead of testing the length of your matches or some such.

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