How do I get a the list that split() didn't return in VIM?s

In VIM, if I do a :echo split('abcd123ef4ghij56k', '\d\+'), the representation of the list [abcd', 'ef', 'ghij', 'k'] is printed. But I am looking for a behaviour that prints what split() did not return, in this case: ['123', '4', '56'].

Of course, in a simple example like here, I could change the pattern to \D\+ in order to get what I want. Yet, this is not what I am after because the pattern is an argument in a function and I think I don't know how to opposite the patter开发者_Go百科n.

Here's a function that returns such a list for an expression:

function! MatchMultiplePatterns(txt, re) 

  let l:result = []

  let l:pos = match(a:txt, a:re)

  while l:pos != -1

        let l:matchedString = matchstr(a:txt, a:re, l:pos)
        let l:result += [l:matchedString]

        let l:pos = match(a:txt, a:re, l:pos + strlen(l:matchedString))

  endwhile

  return l:result

endfunction

But I believe this should be possible without a while-loop and calling match() twice.

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Not sure if this is a good solution in the general case, but…

:echo split('abcd123ef4ghij56k', '\d\zs\ze\D\|\D\zs\ze\d')
['abcd', '123', 'ef', '4', 'ghij', '56', 'k']
:echo split('abcd123ef4ghij56k', '\d\@<=\D\@=\|\D\@<=\d\@=')
['abcd', '123', 'ef', '4', 'ghij', '56', 'k']

splits on digit-to-nondigit and nondigit-to-digit boundaries.

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I've tried to use negative patterns with no luck (I always have troubles with their logic). Anyway. If you really wish to have something short, we can always have a one-liner based on several calls to substitute that replaces what is in between two occurrences of the pattern by '#', and then finally split on '#'

Otherwise, I'd use match() and matchend() + the_full_string[begin:end] to implement the function you have implemented.