I'm using a very simple function:
function closeConn(){
mysql_close($conn);
}
$conn
is the connection variable - it connects ok but i get this error if i try and call it:
Warning: mysql_close() expe开发者_如何转开发cts parameter 1 to be resource, null given in
What is the reason for this?
The reason is, $conn
variable is empty.
Either pass it as an argument to your function:
function closeConn($conn){
mysql_close($conn);
}
closeConn($conn);
or just don't use it at all and let PHP decide which connection to close (by default, tha last one that was opened)
function closeConn(){
mysql_close();
}
or just don't close the connection at all. PHP does it for you anyway, when the script's execution ends.
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