I have string as follows:
s = 'key1=1234 key2="string with space" key3="SrtingWithoutSpace"'
I want to convert in to a dictionary as follows:
k开发者_运维问答ey | value -----|-------- key1 | 1234 key2 | string with space key3 | SrtingWithoutSpace
How do I do this in Python?
The shlex class makes it easy to write lexical analyzers for simple syntaxes resembling that of the Unix shell. This will often be useful for writing minilanguages, (for example, in run control files for Python applications) or for parsing quoted strings.
import shlex
s = 'key1=1234 key2="string with space" key3="SrtingWithoutSpace"'
print dict(token.split('=') for token in shlex.split(s))
Try this:
>>> import re
>>> dict(re.findall(r'(\S+)=(".*?"|\S+)', s))
{'key3': '"SrtingWithoutSpace"', 'key2': '"string with space"', 'key1': '1234'}
If you also want to strip the quotes:
>>> {k:v.strip('"') for k,v in re.findall(r'(\S+)=(".*?"|\S+)', s)}
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