JavaScript regex for alphanumeric string with length of 3-5 chars

I need regex for validating alphanumeric String with length of 3-5 chars. I tried following regex found from the web, but it didn't even catch alphanumerics corre开发者_StackOverflow中文版ctly.

var myRegxp = /^([a-zA-Z0-9_-]+)$/;
if(myRegxp.test(value) == false)
{
    return false;
}

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add {3,5} to your expression which means length between 3 to 5

/^([a-zA-Z0-9_-]){3,5}$/

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You'd have to define alphanumerics exactly, but

/^(\w{3,5})$/ 

Should match any digit/character/_ combination of length 3-5.

If you also need the dash, make sure to escape it (\-) add it, like this: :

/^([\w\-]{3,5})$/ 

Also: the ^ anchor means that the sequence has to start at the beginning of the line (character string), and the $ that it ends at the end of the line (character string). So your value string mustn't contain anything else, or it won't match.

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First this script test the strings N having chars from 3 to 5.

For multi language (arabic, Ukrainian) you Must use this

var regex = /^([a-zA-Z0-9_-\u0600-\u065f\u066a-\u06EF\u06fa-\u06ff\ufb8a\u067e\u0686\u06af\u0750-\u077f\ufb50-\ufbc1\ufbd3-\ufd3f\ufd50-\ufd8f\ufd92-\ufdc7\ufe70-\ufefc\uFDF0-\uFDFD]+){3,5}$/;  regex.test('мшефн');

Other wise the below is for English Alphannumeric only

/^([a-zA-Z0-9_-]){3,5}$/

P.S the above dose not accept special characters

one final thing the above dose not take space as test it will fail if there is space if you want space then add after the 0-9\s

\s

And if you want to check lenght of all string add dot .

var regex = /^([a-zA-Z0-9\s@,!=%$#&_-\u0600-\u065f\u066a-\u06EF\u06fa-\u06ff\ufb8a\u067e\u0686\u06af\u0750-\u077f\ufb50-\ufbc1\ufbd3-\ufd3f\ufd50-\ufd8f\ufd92-\ufdc7\ufe70-\ufefc\uFDF0-\uFDFD]).{1,30}$/;