Regex to remove word from XSLT

I need help writing regex to remove a word using XSLT.

I need to change the output of my XML 开发者_运维问答file's "detailpath" from:

/events/262/26207

...to simply:

262/26207

The XSL is:

<xsl:value-of select="detailpath"/>

How can I remove "/events/"?

Thanks in advance.

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The regex pattern would simply be '/events/'

You can use it in an XSLT 2.0 replace() function call:

<xsl:value-of select="replace(detailpath,'/events/','')"/>

function returns the xs:string that is obtained by replacing each non-overlapping substring of $input that matches the given $pattern with an occurrence of the $replacement string.

You can optionally specify flags

fn:replace( $input     as xs:string?,
            $pattern   as xs:string,
            $replacement   as xs:string) as xs:string

fn:replace( $input     as xs:string?,
            $pattern   as xs:string,
            $replacement   as xs:string,
            $flags     as xs:string) as xs:string

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Do note that for your example (starting string) you could alse use this XPath 1.0 expression:

substring(detailpath, 9 * starts-with(detailpath,'/events/'))

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Another XPath 1.0 solution (assuming there is only one instance of the string to replace) that would work regardless of where the text fragment is in the string:

<xsl:value-of select="concat(substring-before(detailpath,'/events/'), 
                             substring-after(detailpath,'/events/'))" />

---

echo /events/262/26207 | sed -e 's|/events/||g'

This works in bash on Solaris and, with tweaking, should work in PHP, Javascript and Perl, to my knowledge.