How do you make this ajax example work on opera and firefox?_问答_开发者

How do you make this ajax example work on opera and firefox?

开发者 https://www.devze.com 2023-02-06 01:16 出处：网络

I have a quick question, the following only works on IE 7 and above, how can I make it work on firefox and opera aswell?

<html>
<head>
<script type="text/javascript">
function loadXMLDoc()
{
var xmlhttp;
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("myDiv").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","http://www.tdsoft.se/index.html",true);
xmlhttp.send();
}
</script&开发者_StackOverflow社区gt;
</head>
<body>

<div id="myDiv"><h2>Let AJAX change this text</h2></div>
<button type="button" onclick="loadXMLDoc()">Change Content</button>

</body>
</html>

Edit

Thanks for all your answers, now I just have another question regarding the followng code

<html>
<head>
<script type="text/javascript">
function loadXMLDoc()
{
var xmlhttp;
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    return xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","index.html",true);
xmlhttp.send();


}
</script>
</head>
<body>

<div id="myDiv"><h2>Let AJAX change this text</h2></div>
<button type="button" onclick="loadXMLDoc()">Change Content</button>

</body>
</html>

Now I want to search through the xmlhttp.responseText (in other words call the function loadXMLDoc()) for key words, like for example "testfile" and if it exists multiple example "testfile_1" and "testfile_2"....."testfile_n" then "doSomething"

like this

function searchADocument(wordToSearchFor){
int numberOfTimesWordOccurs=0;
var thePageToSearchThrough [] = loadXMLDoc();
for (i=0; i<thePageToSearchThrough.length; i++){
if(thePageToSearchThrough[i]==wordToSearchFor)
 numberOfTimesWordOccurs++;
}
If  (wordToSearchFor > 1) 
document.write("<a href="http://selnc05.go.se:8080/component_test/build/testfile_1">    testfile_1</a>"<a href="http://selnc05.go.se:8080/component_test/build/testfile_2">    testfile_2</a><a href="http://selnc05.go.se:8080/component_test/build/testfile_n">    testfile_n</a>

)

Else

window.location="http://selnc05.go.se:8080/component_test/build/testfile.html";

}

I don't know where to start since I don't know what type xmlhttp.responseText is, can I store it in an array and scan it using for loop etc? Thanks in advance. =)

Try something like this:

ajax("http://www.tdsoft.se/index.html", function(data) {
    document.getElementById("myDiv").innerHTML = data;
});

Code

function getXmlHttpObject() {
    var xmlHttp;
    try {
        xmlHttp = new XMLHttpRequest();
    } catch (e) {
        try {
            xmlHttp = new ActiveXObject("Msxml2.XMLHTTP");
        } catch (e) {
            xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
        }
    }
    return xmlHttp;
}

function ajax(url, onSuccess, onError) {
    var xmlHttp = getXmlHttpObject();
    xmlHttp.onreadystatechange = function () {
        if (this.readyState == 4) {
            if (this.status != 200) {
                if (typeof onError == 'function') {
                    onError(this.responseText);
                }
            }
            else if (typeof onSuccess == 'function') {
                onSuccess(this.responseText);
            }
        }
    };
    xmlHttp.open("GET", url, true);
    xmlHttp.send(null);
    return xmlHttp;
}