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codeigniter will not show info from database

开发者 https://www.devze.com 2023-02-05 23:36 出处:网络
Hello all i have a problem that my information is not being sendt to my view file.开发者_StackOverflow社区

Hello all i have a problem that my information is not being sendt to my view file.开发者_StackOverflow社区

it says: Message: Undefined variable: queryWall

my controller is this

function wallShow() 
 {
  $this->load->model('profil_model');
  $data['queryWall'] = $this->profil_model->wallGet($this->uri->segment(3));


  $data['content'] = 'profil_view';
  $this->load->view('includes/template', $data);
 }

my model:

function wallGet($name)
 {
  $this->db->select('profileName', 'wallComment');
  $this->db->where('profileName', $name);
  $queryWall = $this->db->get('profileWall');

  if($queryWall->num_rows() > 0)
  {
   return $queryWall->result();
  } else {
   return false;
  }
 }

and my view file

 <?php 
 if(!isset($queryWall)):
  foreach ($queryWall as $wall):
   echo $wall->wallComment;
  endforeach;
 endif;
 ?>


Even if everything is fine, you'll keep getting this error since you are using the queryWall variable whenever it's NOT defined!

if(!isset($queryWall))

It should be:

if(isset($queryWall))

But since you are passing the conditional check, then I suppose you have something wrong with your model OR URI segment.


You are not using the correct syntax for

$this->db->select('profileName', 'wallComment');

Adjust it to this:

$this->db->select('profileName,wallComment');

then also enable the out profiler to verify your query is being written correctly by the database class. In your controller, enable the profiler:

$this->output->enable_profiler(true); 

This can be inserted anywhere in the controller function.

I agree with ifaour about making sure your if statement is what you meant it to be.

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